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irina1246 [14]
2 years ago
15

The circle has a Circumference of a 9.42units. What is the area of the square? Use 3.14

Mathematics
1 answer:
kifflom [539]2 years ago
3 0

The area of a square is the square of its side. The area of the square is 2.2477 units².

<h3>What is the area of a square?</h3>

The area of a square is the square of its side. It is given by the formula,

Area of the square = a²

Given the circumference of the circle is 9.42 units. Therefore, the radius of the circle can be written as,

Circumference of the circle = 2πr

\rm9.42\ units= 2\pi r\\\\r = \dfrac{9.42}{2\pi}\ units

Now, as the side of the square is equal to the radius of the circle, therefore, the area of the circle will be equal to,

Area of the circle = a² = r²

\rm \text{Area of the circle }=  (\dfrac{9.42}{2\pi})^2

                            \rm =  \times \dfrac{9.42}{2\pi} \times \dfrac{9.42}{2\pi}\\\\ = 2.2477\ units^2

Hence, the area of the square is 2.2477 units².

Learn more about Area of square:

brainly.com/question/1658516

#SPJ1

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Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *
Luda [366]

Answer:

The answer to your question is   \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1          

Step-by-step explanation:

Data

Foci  (-2, 2)  (4, 2)

Major axis = 10

Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

                  2c = 6

                    c = 6/2

                    c = 3

3.- Determine a

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                    a = 10/2

                    a = 5

4.- Determine b using the Pythagorean theorem

                   a² = b² + c²

-Solve for b

                   b² = a² - c²

                   b² = 5² - 3²

                   b² = 25 - 9

                   b² = 16

                   b = 4

5.- Find the center (1, 2)  From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

                      \frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1

                       \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1                

3 0
3 years ago
A 95-foot wire attached from the top of a cell phone tower makes a 62 degree angle with the ground. Joey is standing 150 feet be
a_sh-v [17]

Answer:

23.32 degrees

Step-by-step explanation:

We set up a large right triangle that has 2 triangles within it.  The large triangle is a right triangle.  The height of it is the height of the tower, the base angle is 62, the hypotenuse is 95, and the base measure is y.  The other triangle has the same height which is the height of the tower, the angle is what we are looking for, and the base measure is 150 feet beyond y, so its measure is y + 150.  We have enough information to find the height of the tower, so let's do that first.  Going back to the first smaller triangle.  

sin62=\frac{x}{95} so the height of the tower is 83.88 feet.  Now we need to solve for y.  Using that same triangle and the tangent ratio, we find that tan62=\frac{83.88}{y}.  Now let's do the same thing for the other triangle with the unknown angle.

tan\beta =\frac{83.88}{y+150}

Solve both of these for y.  The first one solved for y:

y=\frac{83.88}{tan62}

The second one solved for y will simplify to:

y=\frac{83.88-150tan\beta }{tan\beta }

Now that these are both solved for y, and y = y, we can set them equal to each other by the transitive property of equality:

\frac{83.88-150tan\beta }{tan\beta }=\frac{83.88}{tan62}

Cross multiply to get this big long messy looking thing:

tan62(83.88-150tan\beta )=83.88tan\beta

Distribute through the parenthesis to get

83.88tan62-[(tan62)(150tan\beta)]=83.88tan\beta

Get the unknown angles on the same side so it can be factored out:

83.88tan62=83.88tan\beta +[(tan62)(150tan\beta )]

And then factoring it out gives you:

83.88tan62=tan\beta(83.88+150tan62)

Divide to get

tan\beta =\frac{83.88tan62}{83.88+150tan62}

Do this on your calculator in degree mode to give you an angle measure of 23.32°.  I know this is really hard to follow without being able to draw the pics for you like I do in my classroom, but hopefully you can follow my description and draw your own triangles and follow from that!

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What is an equation of the line that passes through the points (-8, 1) and(7,1)?
likoan [24]

Answer:

y=1

Step-by-step explanation:

you can use those points to find the slope

use the equation \frac{y_{1} - y_{2}}{x_{1}-x_{2}} then plug in the numbers

so (1-1)/(-8-7) = 0/15 so the slope is zero meaning it is a horizontal line which we can tell logically because the y coordinates of both points are 1.

so if you plug those numbers into the formula y=mx+b where m is slope and b is the y intercept then

you get y=0*x+1

then 0*x is just zero and it goes away so the equation for this line is y=1

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3 years ago
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Makovka662 [10]

Answer:

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Step-by-step explanation:

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20) Multiply both sides of the equation by 2 to get: -8 + x = -4. So, x = 4

21) Add 3 to both sides to get: \frac{b}{14} = -1. So, b = -14

22) Use the distributive property to get rid of the parentheses. You will get: -40 - 5x = -50. Then, add 40 to both sides to get: -5x = -10. So, x = 2.

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