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3 years ago

I need this to be 20 letters so whats 2 +2

Mathematics

1 answer:

Firdavs [7]3 years ago

5 0

Answer: So what is two plus two plus two?

Well let me demonstrate. Take 2 cookies for example, your friend supplements 2 more cookies and there you have it 4 cookies. So two and two cookies are 4 cookies. Thus, 2+2=4

Step-by-step explanation: Hope I helped you out <3

-Carrie

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a long board 4.7 thick is cut into three pieces of equal length these three pieces are then stacked the stack is cut in three eq

nalin [4]

The number of pieces per stack after 3 cuts represented by a power expression can be written as $3^{3}$

The number of equal pieces per cut = 3

The number of cuts made = 3

Using a power expression :

The number of of equal pieces per cut is raised to a power which represents the number of cuts made

Thus we have $number\: of \:equal\: pieces^{number\: of \:cuts}$

After 1 cut ; $3^{1} = 3$
After 2 cuts ; $3^{2} = 3\times3 = 9$
After 3 cuts ; $3^{3} = 3\times3\times3 = 27$

Therefore, the Number of pieces present in stack after 3 cuts is $3^{3}$

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5 0

3 years ago

Which is the graph of y = 3^ cube root x+1-2

SVETLANKA909090 [29]

Answer:

Plot[-1 + 3^Surd[x, 3], {x, -20, 28}]

6 0

3 years ago

A quantity b varies jointly with c and d and inversely with eWhen b is 18, c is 4, d is 9, and e is 6What is the constant of var

777dan777 [17]

Answer:

constant of variation = 3

Step-by-step explanation:

we know that b varies jointly with c and d

so:

b∝c∝d

and b varies inversely with e, so

b∝ $\frac{1}{e}$

and i will call the constant of variation k, this way we can make an equation for b in the following form:

$b=k\frac{cd}{e}$

this satisfy that b varies jointly with c and d (if b increases, c and d also increase) and inversely with e (if b increases, e decreases)

we know that when b is 18, c is 4, d is 9, and e is 6:

$b=18\\c=4\\d=9\\e=6$

substituting this in our equation for b:

$b=k\frac{cd}{e}\\ 18=k\frac{(4)(9)}{6}$

and we solve operations and clear for the constant of variation k:

$18=k\frac{36}{6}\\ 18=6k\\\frac{18}{6}=k\\ 3=k$

the constant of variation is 3.

4 0

3 years ago

Read 2 more answers

A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On

uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

$h(x)=ax(x-7)$ ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

$4=a(3)((3)-7)$

$4=a(3)(-4)$

$\dfrac{4}{(3)(-4)}=a$

$-\dfrac{1}{3}=a$

Putting $a=-\dfrac{1}{3}$ , we get

$h(x)=-\dfrac{1}{3}x(x-7)$ ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

$h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)$