Answer:
200.86
Step-by-step explanation:
Using the formulas:
A=πr2
C=2πr
Solving for A:
A=C2
4π=50.242
4·π≈200.85812
I hope this helps.
Answer:
21.56
Step-by-step explanation:
Answer: yes they probably are because they can be any size
A. solve for 1 variable
let's solve for x in 2nd equation
add 2y to both sides
x=2y+4
sub 2y+4 for x in other equation
3(2y+4)+y=5
6y+12+y=5
7y+12=5
minu12 both sides
7y=-7
divide 7
y=-1
sub back
x=2y+4
x=2(-1)+4
x=-2+4
x=2
(2,-1)
B. eliminate
eliminate y's
multiply first equation by 2 and add to first
6x+2y=10
<u>x-2y=4 +</u>
7x+0y=14
7x=14
divide by 7
x=2
sub back
x-2y=4
2-2y=4
minus 2
-2y=2
divide -2
y=-1
(2,-1)
(2,-1) is answer
The answer is the first option.
