Answer and Step-by-step explanation: P(X) calculated by the binomial probability formula is:
P(X) =
.
P(20) = ![\left[\begin{array}{ccc}53\\20\end{array}\right] .(0.3)^{20}.(1-0.3)^{33}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D53%5C%5C20%5Cend%7Barray%7D%5Cright%5D%20.%280.3%29%5E%7B20%7D.%281-0.3%29%5E%7B33%7D)
P(20) = 
P(20) = 0.0552
To determine whether the normal distribution can be used to estimate this probability, both n.p and n.(1-p) must be greater than 5:
n . p = 53*0.3 = 15.9
n.(1-p) = 53(1-0.3) = 37.1
Since both ARE greater than 5, normal distribution can be used.
To approximate:
mean = n . p = 15.9
standard deviation =
= 3.34
Find the z-score:
z =
= 
z-score = 0.8907
Comparing values:
0.8907 - 0.0552 = 0.8355
Alright so one dozen cookies is 12 cookies. So 40 dozen cookies is 480 cookies (40x12). If there’s 157 students then u divide 480 by 157 which gets u 3.06 cookies per person
Answer:
4th option is correct
Step-by-step explanation:
Answer : False
It’s possible for a function to have the same output for multiple inputs. This is still considered a function.
well, first off, we do a quick prime factoring of the leading term's coefficient, 35, and the constant, 16.
35 = 5*7
16 = 2*2*2*2
and the rest is just a mix and match.
what combination from the factors of 35 and the factors of 16, can provide a product whose sum is the middle term 26? well, without further adieu.
we can try 5*2*2 + 7*2*2, and that's 20 and 28, ok, 28 - 20 is 8, so that won't work.
another can be 5*2*7 and 2*2, that's 70 and 4, 70 - 4 is 56, that won't work either.
5*2*2*2 and 7*2, that's 40 and 14, hmmm 40 - 14 = 26!!! holly guacamole!
so then,
