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2 years ago

How do I find a least common denominator?

Mathematics

2 answers:

Kitty [74]2 years ago

6 0

Answer:

Below.

Step-by-step explanation:

You can find this by first finding the prime factors of the numbers.

For example, find the LCD of 12 and 16:

12 = 2 * 2 * 3

16 = 2 * 2 * 2 * 2

There are 2 pairs of 2's in the list so only 2 of these four are included in the calculation. All other factors are included.

The LCD is:

2 * 2 * 2 * 2 * 3

= 16*3

= 48.

Find the LCD of 3 and 6

6 = 2 * 3

3 = 3

- so only one of the 3's is included:

LCD = 2*3 = 6.

Afina-wow [57]2 years ago

4 0

Answer:

to find the least common denominator list out the multiples of both denominator until you find the smallest multiple that is shared by both

4: 4,8,12,16,20,24,28,32,

7:14,21,28,35,

because 28 is the first shared multiple of 4 and 7,it most be the least common denominator for these two fractions.

Step-by-step explanation:

hope its help po

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gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

How do I find a least common denominator? ​

How do I find a least common denominator?