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exis [7]
3 years ago
11

Kim went to the grocery store to get some snacks. She bought 3 bags of chips at 89¢ each, 5 candy bars at 50¢ each, and one thre

e-liter bottle of soda at $1.89. She had to pay 8% sales tax.
Mathematics
1 answer:
wariber [46]3 years ago
5 0
The chips all together are 2.67, the candy bars total 2.5, the soda bottle is 1.89$. Add that all together for a total of 7.06. Multiply that by 1.08 to account for taxes and get 7.62.
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would someone be able to explain to me how to solve these problems? I don't need the solutions, I just need an explanation. I ne
Leni [432]
The first 3  are examples of the difference of 2 squares so you use the identity 
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0 
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7  and 7.
Number 7 reduces to 3x^2 =12, x^2  = 4 so x = +/- 2
Number 8  take out GCf (d) to give 
d(d - 2)  = 0   so d = 0 ,  2
9 and 10 are more difficult to factor
you use the 'ac' method  Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end 
that is 2 * 2 =  4
Now we want  2 numbers  which when multiplied give + 4 and when added give - 5:-    -1 and -4  seem promising so we write the equation as:-

2x^2 - 4x - x + 2 = 0

now factor by grouping 
2x(x - 2) - 1(x - 2) = 0

(x - 2) is common so

(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0  and now you can find x.

The last example is solved in the same way.


8 0
3 years ago
Find a irrational number between 7.7 and 7.9 explain why it’s irrational
Alexeev081 [22]
7.77777777 repeating

Irrational numbers are:

Numbers that repeat 
7.7777777 repeats the number 7 after the decimal

Numbers that CANNOT be written as a simple fraction.
7.7777777 cannot be written as a fraction in simplest form.

Answer = 7.777777777 repeating

~Aamira~

Hope this helped :)
8 0
3 years ago
Read 2 more answers
What is the trignometric ration for cos C?<br><br><br><br>____/____
tatiyna

cos\alpha=\frac{adjacent}{hypotenuse}


cosC = \frac{45}{51}

4 0
3 years ago
Read 2 more answers
A couple of college students frustrated with the current class registration process decide to survey 500 random students on camp
aleksklad [387]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Standard deviation = \sqrt{(n*p)(1 - p)}

Substitute the values in:

\sqrt{(500 *0.84)(1-0.84)} = 8.1975...

This can be rounded to give an approximate answer of 8.2

The answer is option A.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

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8 0
3 years ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
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