Answer:
5) Part A: The rate of change, also known as the slope, is the "0.6x" part of the equation. It means that for every week the puppy is alive, x, that number is multiplied by 0.6 pounds.
Part B: The y-intercept is 4 pounds, which represents a puppy being 4 pounds at birth.
Part C: y = 0.6x + 4
y = 0.6(8)+4
y = 8.8
At 8 weeks, a puppy is estimated to be 8.8 pounds.
Part D: y = 0.6x + 4
22 = 0.6 + 4
-4 -4
18 = 0.6x
18/0.6 = 0.6x/0.6
30 = x
It would take a puppy 30 weeks to reach 22 pounds.
Hello!
This is a problem about the general solution of a differential equation.
What we can first do here is separate the variables so that we have the same variable for each side (ex.
with the
term and
with the
term).


Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

Then here, we just solve for
and we have our general solution.
![y=\sqrt[3]{\frac{1}{2}x^2-x+C}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B2%7Dx%5E2-x%2BC%7D)
We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.
Hope this helps!
I think 4 and 6 lcm is 12
Set up multiplication of ratios so that they cancel out units that you do not need in your final answer...
5lb($4.20/2lb)=$10.50
2x^3 + 2x^2 + 5x + 1/ x^2