, or 8.60
Just use the distance formula
Answer:
Solution given:
<ABC and <QRS are supplementary angles.
<ABC = 91°
we have
<ABC +<QRS=180°[supplementary]
<QRS=180°-91°=89°
m<QRS=89°
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:


Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
For this case we have the following equation:
H (t) = - 16t ^ 2 + 28t
When the dolphin finishes a jump, then the height is equal to zero.
We have then:
-16t ^ 2 + 28t = 0
We look for the roots of the polynomial:
t1 = 0
t2 = 1.75 s
Therefore, the dolphin takes 1.75 seconds to make a jump.
Answer:
it will take for the dolphin to make one jump about:
t = 1.75 s
In the 5/4 = ?/12 .. you have to solve if 4 goes into 12 that is 3. 4•3 equals 12. Now you have to multiply 5•3 and it will fill in your blank space. I hope this Helps.