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2 years ago

Find the volume of the sphere. Round your answer to the nearest tenth.

Mathematics

1 answer:

scoundrel [369]2 years ago

7 0

Answer:

Step-by-step explanation:

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Jason volunteered at the pet shelter twice as many times as keith. Noah volunteered three times more often than jason. Keith vol

Alchen [17]

Answer:

$y = 6\cdot z$

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

Step-by-step explanation:

After reading the statement of the problem, the following variables are described below:

$x$ - Number of times that Jason volunteered at pet shelter.

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

The following two relations are presented herein:

Noah and Jason

$y = 3\cdot x$

Jason and Keith

$x = 2\cdot z$

The relationship between the number of times Noah and Keith volunteered is:

$y = 6\cdot z$

7 0

3 years ago

What is 2/5 as a decimal

Natali5045456 [20]

Answer:

0.4

Step-by-step explanation:

2/5 = 4/10

5 0

3 years ago

Read 2 more answers

Pls help im really bad at math no links pls

lawyer [7]

Answer:

$-\frac{1}{2}$

Step-by-step explanation:

$-\frac{5}{6} +\frac{6}{18}$

$-\frac{5}{6} +\frac{2}{6}$ reduced

$\frac{-5+2}{6}$ transformed the expression to make it easier

$-\frac{3}{6}$ add

$-\frac{1}{2}$ reduce

8 0

2 years ago

1 1/2 as a fraction

Alik [6]

Answer:

1.5

Step-by-step explanation:

divide 1/2 and add 1

4 0

3 years ago

Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose

yawa3891 [41]

Answer:

$V=5\sqrt{3}\ m^3$

Step-by-step explanation:

we know that

The volume of a trough is equal to

$V=BL$

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

$B=\frac{1}{2} b^{2} sin(60\°)$

where

$b=2\ m$

$sin(60\°)=\frac{\sqrt{3}}{2}$

substitute

$B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})$

$B=\sqrt{3}\ m^{2}$

step 2

Find the volume of a trough

$V=BL$

we have

$B=\sqrt{3}\ m^{2}$

$L=5\ m$

substitute

$V=(\sqrt{3})(5)$

$V=5\sqrt{3}\ m^3$

3 0

3 years ago