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IceJOKER [234]
2 years ago
10

Please help! I really need help I have more questions that I'll post after​

Mathematics
2 answers:
iris [78.8K]2 years ago
8 0

Answer:

$6

Step-by-step explanation:

48÷8=6

keep the questions coming

GarryVolchara [31]2 years ago
3 0

Answer:

6.25

Step-by-step explanation:

c

You might be interested in
3 l = _____ dl<br><br> A. 0.3<br> B. 0.03<br> C. 300<br> D. 30
Andru [333]

Answer: The correct option is D, i.e.,30.

Explanation:

It the given equation we have two units l and dl.

Where l represents the liter and dl represents the deciliter. These are the volume units.

We know that,

1 liter = 10 deciliter

It means,

1 l = 10 dl

Multiply both sides by 3,

1\times 3 l = 10\times 3 dl

3 l = 30 dl

Therefore, the correct option is D and 3 l = 30 dl.

6 0
3 years ago
Solve the equation. Check your answers.<br>29=7x+5-4x​
Vladimir [108]

Answer:

x = 8

Step-by-step explanation:

29=7x + 5 -4x

add like terms: 29 = 3x +5

get your x variable on one side

24 = 3x

divide by 3

x = 8

check!

29 = 7(8) + 5 -4(8)

29 = 56 + 5 -32

29 = 51 - 32

29 = 29

6 0
3 years ago
Find all solutions of each equation on the interval 0 ≤ x &lt; 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
2 years ago
Read 2 more answers
The table shows values for points on the graph of a linear function.
Anna [14]
(x2-x1)/(y2-y1)

(1+2)/(1-13)


3/-12


the slope of the graph is -1/4
8 0
3 years ago
PLEASE!!!!!! URGENT!!!! WILL GIVE BRAINLIEST!!!!!!!!!!!!
choli [55]
I think the answer is D
3 0
2 years ago
Read 2 more answers
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