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3 years ago

Please help! I really need help I have more questions that I'll post after

Mathematics

2 answers:

iris [78.8K]3 years ago

8 0

Answer:

Step-by-step explanation:

48÷8=6

keep the questions coming

GarryVolchara [31]3 years ago

3 0

Answer:

6.25

Step-by-step explanation:

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Amanda [17]

Answer:

If the ball cost 10 cents and the bat costs $1.00 more than the ball, then the bat would cost $1.10 for a grand total of $1.20. The correct answer to this problem is that the ball costs 5 cents and the bat costs — at a dollar more — $1.05 for a grand total of $1.10.

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Lyrx [107]

According to the options given yes

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Paul [167]

Answer:

1 and 1/6

Step-by-step explanation:

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3 years ago

Uhh solve the question? i hope i find some haikyuu stans out there✌️

musickatia [10]

Answer and Step-by-step explanation:

$(\frac{1.25 - x}{1.25x} ) * 100\\\\\\(\frac{1.25}{1.25x} - \frac{x}{1.25x} ) * 100\\\\(\frac{1}{x} - \frac{1}{1.25} ) * 100\\\\\frac{100}{x} - 80\\\\\\$

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3 years ago

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A study of 35 golfers showed that their average score on a particular course was 92. The sample standard deviation was 5. We wan

svlad2 [7]

Answer:

$t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$

Step-by-step explanation:

We have a sample of size n = 35, $\bar{x} = 92$ and $s = 5$ . As we want to construct a 95% confidence interval to estimate the value of the true population mean $\mu$ , we should use the pivotal quantity given by $T = \frac{\bar{X}-\mu}{S/\sqrt{n}}$ which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value $t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$ , i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that $P(-2.0322\leq T\leq 2.0322) = 0.95$ because of the simmetry of the t distribution.

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3 years ago

Please help! I really need help I have more questions that I'll post after​

Please help! I really need help I have more questions that I'll post after