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1 year ago

What is the area of a triangle whose vertices are R(3, 4), S(6, 2), and T(7, 10)?

2 answers:

8 0

Answer: The answer is 15 units². Step-by-step explanation: I am a hundred percent sure. I did the math and got it right on my test.

Step-by-step explanation: ANSWER15 square units.EXPLANATIONThis triangle has one of its height(altitudes) falling outside the triangle.

zavuch27 [327]1 year ago

5 0

Answer:

ANSWER

15 square units.

EXPLANATION

This triangle has one of its height(altitudes) falling outside the triangle.

We determine the base using absolute value method. This is because the coordinates of R(-4,2)R(−4,2) and S(1,2)S(1,2) tell us that this line is horizontal. The y-values are constant.

Therefore |RS|=|1--4|∣RS∣=∣1−−4∣

\Rightarrow |RS|=|1+4|⇒∣RS∣=∣1+4∣

\Rightarrow |RS|=|5|⇒∣RS∣=∣5∣

\Rightarrow |RS|=5⇒∣RS∣=5

Also

The triangle is bounded between y=2y=2 and y=-4y=−4 .

Therefore the vertical height of interest,

|RT|=|-4-2|∣RT∣=∣−4−2∣

|RT|=|-6|∣RT∣=∣−6∣

|RT|=6∣RT∣=6

We can now find the area using the formula

Area=\frac{1}{2}base\times heightArea=21base×height

Area=\frac{1}{2}\times6 \times 5Area=21×6×5

Area=3 \times 5Area=3×5

Area=15Area=15 square units

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