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Olenka [21]
3 years ago
15

Help pleaseeeee picture attached

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

The diagonal of the base is 4√5 centimeters.

The area of a base is 40 square centimeters.

The area of a lateral side between the bases is about 126.5 square centimeters.

Step-by-step explanation:

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What is the surface area of the sphere below?
jeka57 [31]

Answer:

A) 64π units

Step-by-step explanation:

SA= 4πr squared

4*π*4 squared

4 squared = 16

16*4=64

64π

7 0
3 years ago
Read 2 more answers
A silk ribbon costs $5.60 for 0.8m. Find the constant of variation.
Minchanka [31]

Answer: The constant of variation value of 7.


Step-by-step explanation: We are given cost of 0.8 meter of a silk ribbon = $5.60.

Let us assume y be the total cost for x meter of a silk ribbon and k is the  constant of variation.

So, we can set up an equation for proportion relationship:

y = k x.

<em>Let us plug x=0.8 and y= 5.60,</em> in above proportion relationship equation, we get

5.60 = k (0.8).

Dividing both sides by 0.8, we get

5.60/0.8 = k(0.8)/0.8

k =7.

Therefore, the constant of variation value of 7.



6 0
3 years ago
The classes at the middle school want to raise money. The sixth grade runs a bake sale for 55 hours and makes $170. The seventh
Jet001 [13]
The sixth grade runs a bake sale for 55 hours and makes $170.
So in one hour, they made 170/55 = 3.09 dollars.
Rate: $3.09/h

The seventh grade sets up a dunking booth for 44 hours and makes $112.
So in one hour, they made 112/44 = 2.54 dollars.
Rate: $2.54/h

The eight grade has a car wash and makes $192 in 66 hours.
So in one hour, they made 192/66 = 2.90 dollars.
Rate $2.90/h

3.09 > 2.90 > 2.54
So R(6th) > R(8th) > R(7th)

Which means that the sixth grade has the highest rate for raising money.

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
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algol13

Answer:

a

Step-by-step explanation:

the sides a parallel but non of it is a rectangle and it has the distinct shape of a kite.

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3 years ago
The number of students at a school who ate in the cafeteria yesterday can be represented by the expression 4/5k where K is the n
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