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3 years ago

Please help me !!!!!! I will mark brainlest!!!

Mathematics

1 answer:

AysviL [449]3 years ago

6 0

Answer: D

Step-by-step explanation:

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(2/3)^3(1/5•2/3)^-3(1/5)^4 <br><br> PLS HELP

Gnom [1K]

Answer:

1/5

Step-by-step explanation:

You have to do whats in the parentheses first then you start doing to exponets from left to right then you would multiply then you would get your answer 1/5.

4 0

4 years ago

What is the interquartile range of 16,25,12,20,10,25

zhuklara [117]

5.3 because 12+20=32 and 32 divided by 6 = 5.3

3 0

4 years ago

The perimeter of a rectangular pool is 312 m.

expeople1 [14]

The perimeter of a rectangle is calculated by:

$\boxed{P=width +width+length+ length}$

Remember: In a rectangle, opposite sides are equals.

If we know how much is the width, then it's just apply it to the expression:

$P=width+width+length+length\\312 =68 + 68 + length + length\\312 = 136+(2\cdot length)\\312 - 136 = 2\cdot length\\2\cdot length = 176\\length = \frac{176}{2} \\length = 88$

Therefore, the length of the pool is 88m.

3 0

3 years ago

she has 78 inches of thread that she cut into 2 pieces. One piece is twice as long as the other piece. How long is each piece?

valentinak56 [21]

Answer:

One piece is 26 inches long while the other is 52 inches long.

We let:

x = one piece of the thread

2x = the other piece of the thread

Since the thread is 78 inches long,

2x + x = 78

Solve for x:

$2x+x=78\Rightarrow3x=78$ $\frac{3x}{3}=\frac{78}{3}\Rightarrow x=26$

Since one piece of the thread is 26 inches long, the other piece would be:

$2x=2(26)=52$

The other piece would be 52 inches long.

8 0

1 year ago

Simplify and Show your work

BlackZzzverrR [31]

1. $\frac{ 5( {4x}^{3} {y}^{2} ) ^{3}}{( {4x}^{5} {y}^{3}) ^{4} } \\ = \frac{5 \times {4}^{3} \times {x}^{3 \times 3} \times {y}^{2 \times 3} }{ {4}^{4} \times {x}^{5 \times 4} \times {y}^{3 \times 4} } \\ = \frac{5 \times 64 \times {x}^{9} \times {y}^{6} }{256 \times {x}^{20} \times {y}^{12} } \\ = \frac{320 {x}^{9} {y}^{6} }{256 {x}^{20} {y}^{12} } \\ = \frac{5 {x}^{9 - 20} {y}^{6 - 12} }{4} \\ = \frac{5}{4 {x}^{11} {y}^{6} }$

2. ${3}^{5x - 4} = {9}^{2x + 12} \\ = > {3}^{5x - 4} = {3}^{2(2x + 12)} \\ = > {3}^{5x - 4} = {3}^{4x + 24} \\ = > 5x - 4 = 4x + 24 \\ = > 5x - 4x = 24 + 4 \\ = > x = 28$

Hope you could understand.

If you have any query, feel free to ask.

6 0

3 years ago