If the equation y = 1/3 x + 2 is changed to y = 3x + 2, what will be true about the graph of the equation?
2 answers:
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To solve for a variable, you need to get it (x) by itself.
x² - 14 + 31 = 63 Add 31 to -14
x² + 17 = 63 Subtract 17 from both sides of the equation
x² = 46 Square root both sides
x =
Check your work by plugging in
for x and then 
.
² - 14 + 31 = 63 Square
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63
² - 14 + 31 = 63 Square
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63
So, x is and .
x² - 14 + 31 = 63 Add 31 to -14
x² + 17 = 63 Subtract 17 from both sides of the equation
x² = 46 Square root both sides
x =
Check your work by plugging in
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63
So, x is
Answer: D ) Cube root of 16
Thank you.