Answer:
a) i) The drawing of Zeno's route is attached
ii) The bearing of Zeno's return journey is 241° from point C to point A
b) Yes, Zeno returns to Port A before 5.15pm
Step-by-step explanation:
a) i) Please find attached the drawing of Zeno's route
ii) From the attached diagram of Zeno's route created with Microsoft Whiteboard, we find the bearing of his return journey as 241° from point C to point A
b) The distance from point C to point A = 10·√5 km
The speed with which Zeno sails as he returns = 10 km/h
The time it takes Zeno to return t = Distance/Speed
∴ The time it takes Zeno to return t = 10·√5 km/(10 km/h) = √5 h ≈ 2.2361 hours ≈ 2 hours 14 minutes and 9.845 seconds
The time Zeno arrives at point A from point A ≈ 3.00 pm + 2 hours 14 minutes and 9.845 seconds = 5:14.1641 p.m. ≈ 5:14 pm.
Therefore, Zeno returns to Port A before 5.15pm.
This question is incomplete, the complete question is;
A stock price S is governed by dS = aSdt + bSdz
where z is a standardized Wiener process. Find the process that governs G(t) = S^1/2(t)
Answer:
G = S^1/2
Step-by-step explanation:
Solving the Equation
dS = aSdt + bSdz
First we Take S common from Right hand Side
dS = S(a dt + b dz)
Then we also take S Left Hand Side(LHS) from RHS
dS/S = a dt + b dz
So d = a dt + b dz
now we Take d Common from RHS
d = d(a t + b z)
So
d/d = a t + b z
1 = a t + b z
So, t = (1-b z) / a
Now substitute value of t in equation G(t) = S^1/2(t)
we have
G{(1- b z)/a} = S^1/2 {(1- b z)/a}
(1- b z)/a) from both sides cancels out each other
So we have G = S^1/2
28+24=52
So we make a sum of what's going to equal 52 in small packets.
I found 4x13=52. 13 would be the number of packets......
BUT!! Since it MUST be equal dark and milk and we have 28 and 26,
you would have to eliminate 1 pack because all 4 would be milk chocolate.
So that is only 12 packets.
4 per pack so that would be 2 dark and 2 milk per packet.
okay so angle 11 can be equivalent to angle 16,3, and 8 but they're probably looking for angle 3
angle 16 can be equivalent to 11, 3, and 8 but they're probably looking for 8
angle 6 is 90 degrees so anything that is also 90 degrees will equal 180 degrees
lines U and J are perpendicular
also I did this 2 years ago so it isn't hard just time consuming
hope this helps :)
