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zhannawk [14.2K]
2 years ago
8

Find the slope of a line with equation 4y + x = 8.

Mathematics
2 answers:
aniked [119]2 years ago
8 0

Answer:

m = -1/4

Step-by-step explanation:

4y + x = 8

Arrange the equation in a slope intercept form y = mx+b, where m is the slope

4y + x = 8, subtract x from both sides

   4y = -x +8, divide both sides by 4

     y = -x/4 + 8/4 , simplify

     y = -x/4 + 2, compare this to the general form y=mx+b and we see that the slope m = -1/4

uranmaximum [27]2 years ago
4 0

Answer:

m = -1/4

Step-by-step explanation:

4y + x = 8

Arrange the equation in a slope intercept form y = mx+b, where m is the slope

4y + x = 8, subtract x from both sides

    4y = -x +8, divide both sides by 4

      y = -x/4 + 8/4 , simplify

      y = -x/4 + 2, compare this to the general form y=mx+b and we see that the slope m = -1/4

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Answer:

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Step-by-step explanation:

3 0
3 years ago
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Una función racional corresponde a una función algebraica o trascendente
Andreyy89

Answer:

Step-by-step explanation:

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6 0
3 years ago
determine the equation of the circle if its center is (8,-6) and which passes through the points (5,-2).
ser-zykov [4K]

Answer:

(x - 8)² + (y + 6)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Here (h, k ) = (8, - 6 ) , then

(x - 8)² + (y - (- 6))² = r² , that is

(x - 8)² + (y + 6)² = r²

The radius is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (8, - 6 ) and (x₂, y₂ ) = (5, - 2 )

r = \sqrt{(5-8)^2+(-2-(-6))^2}

  = \sqrt{(-3)^2+(-2+6)^2}

  = \sqrt{9+4^2}

  = \sqrt{9+16}

   = \sqrt{25}

   = 5

Then equation of circle is

(x - 8)² + (y + 6)² = 5² , that is

(x - 8)² + (y + 6)² = 25

6 0
2 years ago
B) 2x² - 4x + 3 = 0<br> a) x² + 3x – 10 = 0
kozerog [31]

Answer:

a. x = 2 , x = -5

b. no real roots

Step-by-step explanation:

<u>a. x² + 3x – 10</u>

= x² - 2x + 5x - 10

= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)

= (x - 2) (x + 5)

x - 2 = 0                            x + 5 = 0

 + 2    +2                             -5     -5

--------------                         ---------------

x = 2                                   x = -5

x = 2 , x = -5

<u>b. 2x² - 4x + 3 </u>

This can't be solved because the equation has no real roots, and also the discriminant is negative.

3 0
2 years ago
Which of the following are solutions to the system graphed below.
Kisachek [45]
Weird. I think you just need to look if the point falls on the shaded area. But only (-5,5) does ...

4 0
3 years ago
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