Answer:
$927.113
Step-by-step explanation:
50-7=43
43×18.94=814.42
100-15=85
100%=18.94
what about 85%
85×18.94=1609.9÷100=16.099
16.099×7=112.693
814.42+112.693= 927.113
Answer:
D. 127.5 square units
Step-by-step explanation:
AC=17
BD=15
AB=11.5
Diagonal (1&2) are given, base of the rhombus is also given.
Height is not given
Area of a rhombus given the diagonals
=1/2×d1×d2
Where,
d1=AC=17
d2=BD=15
Area of a rhombus=1/2×d1×d2
=1/2×17*15
=1/2×255
=127.5
D. 127.5 square units
Answer:
Using ∣x∣>a⇒x<−a or x>a, we get
∣3x−7∣>4⇒3x−7<−4 or 3x−7>4
⇒3x<3 or 3x>11⇒x<1 or x>
3
11
⇒x∈(−∞,1)∪(
3
11
,∞).
Answer:
5 square inches
Step-by-step explanation:
First, we need to find the area of one sticky note:
The formula is Lenth*Width
Area of one sticky note:
5/6*2/3=10/18
=5/9 square inches
Now, we find the area of 9 sticky notes:
5/9*9=5
5 square inches
Hope this helps! Have an amazing day!
Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
