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borishaifa [10]
2 years ago
13

Hi I need help on this I've been working on it for about 20 minutes now please help :)

Mathematics
1 answer:
Mama L [17]2 years ago
5 0

Answer:

V = 4 2/3 units ^3

Step-by-step explanation:

We are given the area of the back rectangle

V = BH where B is the area of the base

V = 3 1/3 * 1 2/5

Rewriting the mixed numbers as improper fractions

V = 10/3 * 7/5

V = 70/15

Simplifying

V = 14/3

Changing back to a mixed number

V = 4 2/3 units ^3

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THE VALUE OF 9 IN 495,123 IS 10000 <span>TIMES THE VALUE OF 9 IN 63,129</span>
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3 years ago
We live in the most marketed to culture in the history of the world.<br><br> True <br> False
jenyasd209 [6]
False false false false
7 0
3 years ago
Write the point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5)?
nevsk [136]

The point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5) is y + 1 = 6x + 18

<u>Solution:</u>

Given, two points are (-3, -1) and (-2, 5)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

<em><u>The slope of line "m" is given as:</u></em>

\text { slope of line } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }

Now, let us find the line equation using point slope form

y-y_{1}=m\left(x-x_{1}\right)

where m is slope

\begin{array}{l}{\text { Then, line equation } \rightarrow y-(-1)=6(x-(-3))} \\\\ {\rightarrow y+1=6(x+3)} \\\\ {\rightarrow y+1=6 x+18}\end{array}

Hence the point slope form is y + 1 = 6x + 18

7 0
3 years ago
Which part of the proof does the fourth statement and reason represent?
denis-greek [22]

Answer:

Option B is correct.

Reason:It is an argument

Step-by-step explanation:

Given: AB \cong BC  and BC \cong EF

By transitive property:  a = b  and b = c then, a =c

⇒AB \cong EF

AB = EF                                [def of \cong segment]

By Segment Addition Postulate states that given  two points A and C, and a third point B lies on the line segment AC if and only if the distances between the  points satisfy the equation

AB + BC = AC.

Since, the line segment EG , F lies on the line segment;

then, by segment addition postulates we have;

EG = EF + FG

By substitution AB=EF

⇒ EG = AB + FG                     hence proved!

Since, in the fourth statement reason is:  It is an argument

3 0
3 years ago
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3 years ago
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