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2 years ago

Hi I need help on this I've been working on it for about 20 minutes now please help :)

Mathematics

1 answer:

Mama L [17]2 years ago

5 0

Answer:

V = 4 2/3 units ^3

Step-by-step explanation:

We are given the area of the back rectangle

V = BH where B is the area of the base

V = 3 1/3 * 1 2/5

Rewriting the mixed numbers as improper fractions

V = 10/3 * 7/5

V = 70/15

Simplifying

V = 14/3

Changing back to a mixed number

V = 4 2/3 units ^3

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THE VALUE OF 9 IN 495,123 IS 10000 TIMES THE VALUE OF 9 IN 63,129

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3 years ago

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3 years ago

Write the point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5)?

nevsk [136]

The point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5) is y + 1 = 6x + 18

Solution:

Given, two points are (-3, -1) and (-2, 5)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

The slope of line "m" is given as:

$\text { slope of line } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }$

Now, let us find the line equation using point slope form

$y-y_{1}=m\left(x-x_{1}\right)$

where m is slope

$\begin{array}{l}{\text { Then, line equation } \rightarrow y-(-1)=6(x-(-3))} \\\\ {\rightarrow y+1=6(x+3)} \\\\ {\rightarrow y+1=6 x+18}\end{array}$

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3 years ago

Which part of the proof does the fourth statement and reason represent?

denis-greek [22]

Answer:

Option B is correct.

Reason:It is an argument

Step-by-step explanation:

Given: $AB \cong BC$ and $BC \cong EF$

By transitive property: a = b and b = c then, a =c

⇒ $AB \cong EF$

AB = EF [def of $\cong$ segment]

By Segment Addition Postulate states that given two points A and C, and a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation

AB + BC = AC.

Since, the line segment EG , F lies on the line segment;

then, by segment addition postulates we have;

EG = EF + FG

By substitution AB=EF

⇒ EG = AB + FG hence proved!

Since, in the fourth statement reason is: It is an argument

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3 years ago

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Blababa [14]

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3 years ago