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borishaifa [10]
2 years ago
13

Hi I need help on this I've been working on it for about 20 minutes now please help :)

Mathematics
1 answer:
Mama L [17]2 years ago
5 0

Answer:

V = 4 2/3 units ^3

Step-by-step explanation:

We are given the area of the back rectangle

V = BH where B is the area of the base

V = 3 1/3 * 1 2/5

Rewriting the mixed numbers as improper fractions

V = 10/3 * 7/5

V = 70/15

Simplifying

V = 14/3

Changing back to a mixed number

V = 4 2/3 units ^3

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Solve for x.<br><br><br><br> 2x/3 + 1 = 3<br><br> x = 1 <br> x = 6<br> x = 3<br> x = 2
snow_tiger [21]

Answer:

your answer is x = 3

8 0
3 years ago
A room has dimensions of 8 mx 6 mx 4 m.
natali 33 [55]

Answer:

Price of paint = Rs 16,640

Step-by-step explanation:

As 3 dimensions are given so the third one must be for ceiling.

So in this case, we can find area as follows:

Area = 2(length * width) + 2(length * height)+ 2(height * width)........eq1

Lets say:

Length = 8m

Width = 6m

Height = 4m

So putting value in eq1 we get:

Area = 2(8*6) + 2(8*4) + 2(4*6)

Area = 2(48) + 2(32)+ 2(24)

Area =96 + 64 + 48

Area = 208 sq. m

Now for calculating price:

Price of paint = 208 * 80

Price of paint = Rs 16,640

I hope it will help you!

5 0
3 years ago
HG is the perpendicular bisector of FK.<br> What is the length of GH?<br> 8<br> 9<br> 15<br> 34
igor_vitrenko [27]

Answer:

GH=15

Step-by-step explanation:

HK= FK/2= 16/2= 8

Using pythagoras theorem in triangle GHK,

GH²= GK²-HK²

= 17²-8²

= 225

GH= √225

=15

4 0
3 years ago
Which expression could be used to solve the problem?
Paladinen [302]
THE ANSWER IS D whoops lol sorry i was in an argument lol 
4 0
3 years ago
Simplify 2(a-3)/(a-4)(a-5)+(a-1)/(3-a)(a-4)+(a-2)/(5-a)(a-3)​
Umnica [9.8K]

Answer:

  \dfrac{5}{x^3-12x^2+47x-60}

Step-by-step explanation:

Though it is not what you have written, we think you want to simplify ...

  \dfrac{2(a-3)}{(a-4)(a-5)}+\dfrac{(a-1)}{(3-a)(a-4)}+\dfrac{(a-2)}{(5-a)(a-3)}\\\\=\dfrac{2(a-3)^2}{(a-3)(a-4)(a-5)}+\dfrac{-(a-1)(a-5)}{(a-3)(a-4)(a-5)}+\dfrac{-(a-2)(a-4)}{(a-3)(a-4)(a-5)}\\\\=\dfrac{2(a^2-6a+9)-(a^2-6a+5)-(a^2-6a+8)}{x^3-12x^2+47x-60}\\\\=\boxed{\dfrac{5}{x^3-12x^2+47x-60}}

_____

When writing a fraction in plain text, parentheses are needed around the entire denominator. The order of operations tells you that a/bc = (a/b)c, not a/(bc).

6 0
3 years ago
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