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4 years ago

13m/1m = ?/100cm I need to have this answer quick, please respond as fast as you can, thank you so much

Mathematics

1 answer:

Arte-miy333 [17]4 years ago

3 0

Answer:

The answer is 13 m/1 m = 1300 cm/100 cm.

Step-by-step explanation:

Given:

13m/1m = ?/100cm.

Now, to find the answer in the place of ? .

13m/1m = ?/100cm.

As, 1(m) metre = 100(cm) centimetre.

So, by multiplying 13 m with 100 we get:

$13 m\times 100 = 1300 cm.$

Thus, 13 m/1 m = 1300 cm/100 cm.

Therefore, the answer is 13 m/1 m = 1300 cm/100 cm.

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kompoz [17]

Answer:

x = 11

Step-by-step explanation:

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then 6/(6 + 48) = 5/(5 + 3x + 7)

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3 years ago

Read 2 more answers

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Gekata [30.6K]

That's just too bad. I don't the answer. I'm just doing this to get points. Good luck.

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3 years ago

In a classroom, the ratio of pencils to erasers is 9:4. What is the fraction of the number of erasers to pencils?

jeyben [28]

Answer:

$\frac{4}{9}$

Step-by-step explanation:

The ratio of pencils to erasers is

$9:4$

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$\frac{9}{4}$

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3 years ago

noname [10]

Answer:

The simultaneous inequation representing the recomended storage temperature is:

$50\,^{\circ}F \leq T \leq 55.4\,^{\circ}F$

Step-by-step explanation:

In this case, the statement must be represented mathematically by a simultaneous inequation, in which temperature must be equal to or greater than 10 ºC, expressed in Fahreheit degrees, and equal or less than 13 ºC, expressed in Fahrenheit degrees.

Bounds can be converted into Fahrenheit degrees from Celsius degrees:

$T_{F} = \frac{9}{5} \cdot T_{C}+32\,^{\circ}F$ (Eq. 1)

Where:

$T_{C}$ - Temperature, measured in Celsius degrees.

$T_{F}$ - Temperature, measured in Fahrenheit degrees.

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The simultaneous inequation representing the recomended storage temperature is:

$50\,^{\circ}F \leq T \leq 55.4\,^{\circ}F$

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3 years ago

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prohojiy [21]

So the original price is "x".

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4 years ago

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13m/1m = ?/100cm I need to have this answer quick, please respond as fast as you can, thank you so much​

13m/1m = ?/100cm I need to have this answer quick, please respond as fast as you can, thank you so much