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m_a_m_a [10]
3 years ago
13

Solve for w. 3w+8/2=25 Enter your answer in the box. Please help me!!

Mathematics
2 answers:
Nikitich [7]3 years ago
6 0
W=14<span>
And i put my answer in the box.</span>
Dmitrij [34]3 years ago
5 0
I think it is
\frac{3w+8}{2} =25
multily both sides by 2
3w+8=50
mins 8 both sides
3w=42
divide both sides by 3
w=14
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Answer:

Debbie's Deals has the better deal with a price of $0.19 per ounce compared to Bill's Bargains at $0.21 per ounce.

Step-by-step explanation:

Divide $3.36 by 16 = $0.21

Divide $7.60 by 40 = $0.19

Debbie's Deals sells the Circle O's cereal for a cheaper per ounce price thus it's the better price and the better deal.

Good luck!

7 0
3 years ago
5. Ms. Sellers flew out to Utah to take her sons to college. If she flew 245.6
lara31 [8.8K]

Answer:

Step-by-step explanation:

distance flown in 5.4 hours = 245.6 miles

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8 0
3 years ago
Read 2 more answers
———Help pleaseeeee———
Maslowich

Answer:

Slope of line is \pi

Step-by-step explanation:

Given that the company logo has four concentric circles.

To plot the line on the graph take point as ( Diameter, Circumference )

Circumference of a circle is given by C=\pi D

Where D is the diameter.

To draw a line, we need at least two-point.

Now,

Take D=1

Circumference of a circle will be C=\pi D=\pi

Required point is (1,\pi)

Take D=0

Circumference of a circle will be C=\pi D=0 \pi

Required point is (0,0)

The slope of line is given by s=\frac{Y2-Y1}{X2-X1}

Hence,

s=\frac{Y2-Y1}{X2-X1}

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s=\frac{[tex]\pi}{1}[/tex]

s=\pi

Thus, Slope of line is \pi

7 0
3 years ago
The downward pull on an object due to gravity is the object’s
finlep [7]
<span>The downward pull on an object due to gravity is the object’s </span>Weight

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3 0
3 years ago
Read 2 more answers
Anyone know the answer to this algebra problem?
ikadub [295]

Answer:  \bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}

<u>Step-by-step explanation:</u>

\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}

\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}

3 0
3 years ago
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