Question

The area of a rectangle is 32a^3b^4 square units. The length is 4a^2b. Find the width. show your work

Answer 1

Answer:

The answer to your question is width = 8ab³

Step-by-step explanation:

Data

Area = 32a³b⁴ u²

length = 4a²b   u

Formula

Area of a rectangle = width x length

Solve for width

                           width = $\frac{Area}{length}$

Substitution

                          width = $\frac{32a^{3}b^{4}}{4a^{2}b}$

Simplify using rules of exponents, just remember that in a division we subtract the exponents and divide the coefficients normally.

                          width = 8 a²b³

Answer 2

Answer:

Step-by-step explanation: 32a^3 is -8 < a < - 8 axis interceptions 32a^3            vertical asymphotes None Extreme points of a32a^3 0,0