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kkurt [141]
3 years ago
6

The area of a rectangle is 32a^3b^4 square units. The length is 4a^2b. Find the width. show your work

Mathematics
2 answers:
kaheart [24]3 years ago
7 0

Answer:

The answer to your question is width = 8ab³

Step-by-step explanation:

Data

Area = 32a³b⁴ u²

length = 4a²b   u

Formula

Area of a rectangle = width x length

Solve for width

                           width = \frac{Area}{length}

Substitution

                          width = \frac{32a^{3}b^{4}}{4a^{2}b}

Simplify using rules of exponents, just remember that in a division we subtract the exponents and divide the coefficients normally.

                          width = 8 a²b³

erma4kov [3.2K]3 years ago
7 0

Answer:

Step-by-step explanation: 32a^3 is -8 < a < - 8 axis interceptions 32a^3            vertical asymphotes None Extreme points of a32a^3 0,0

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stepan [7]

Answer:

Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

Step-by-step explanation:

As Nora's paper airplane flew 9 1/6 feet

i.e.

9\frac{1}{6}=\frac{55}{6}

Nora's paper was farther than Max's plane flew by = 2 3/4 feet

i.e.

2\frac{3}{4}=\frac{11}{4}

Thus the equation to show how far Max's paper airplane flew is:

\:\:9\frac{1}{6}-2\frac{3}{4}

=\frac{55}{6}-\frac{11}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}6,\:4:\quad 12

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

=\frac{110}{12}-\frac{33}{12}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{110-33}{12}

\mathrm{Subtract\:the\:numbers:}\:110-33=77

=\frac{77}{12}

=6\frac{5}{12}

Therefore, Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

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The simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.

First we must simplify the expression:
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Then we rationalize the expression:
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<span>Finally, the simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.</span>
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