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kkurt [141]
3 years ago
6

The area of a rectangle is 32a^3b^4 square units. The length is 4a^2b. Find the width. show your work

Mathematics
2 answers:
kaheart [24]3 years ago
7 0

Answer:

The answer to your question is width = 8ab³

Step-by-step explanation:

Data

Area = 32a³b⁴ u²

length = 4a²b   u

Formula

Area of a rectangle = width x length

Solve for width

                           width = \frac{Area}{length}

Substitution

                          width = \frac{32a^{3}b^{4}}{4a^{2}b}

Simplify using rules of exponents, just remember that in a division we subtract the exponents and divide the coefficients normally.

                          width = 8 a²b³

erma4kov [3.2K]3 years ago
7 0

Answer:

Step-by-step explanation: 32a^3 is -8 < a < - 8 axis interceptions 32a^3            vertical asymphotes None Extreme points of a32a^3 0,0

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