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evablogger [386]

3 years ago

5

A crate containing four identical cartridges weighs 5 kilograms (kg). If the weight of the crate is 600 grams (g), what is the w

eight of each crate?

1 answer:

mel-nik [20]3 years ago

8 0

Answer: 1100 grams

Step-by-step explanation:

5kg=5000g

5000g-600g=4400g

4400g/4=1100g

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a triangle with vertices at A (-1,1), B(-2,1) C(-1,4) is translated. the image of vertex A has coordinate at (3,-1) determine th

Drupady [299]

For this case we have the following vertices:
A (-1,1) --------> A '(3, -1)
B (-2.1)
C (-1,4)
We note that the translation rule is:
(x, y) -----------> (x + 4, y-2)
Applying the translacion rule we have:
B (-2, 1) -----------> (-2 + 4, 1-2) ------> B '(2, -1)
C (-1, 4) -----------> (-1 + 4, 4-2) ------> C '(3, 2)
Answer:
The image of vertex B or the image of Vertex C are:
B '(2, -1)
C '(3, 2)

7 0

3 years ago

What is the difference between the smallest 7-digit number and the largest 6-digit number?

gogolik [260]

Answer:

the greatest 7 digit no.is = 999,99,99 the smallest 6 digit no.is= 1,00,000

Step-by-step explanation:

Sorry if I'm wrong I tried.

5 0

1 year ago

A car is 120 inches long. A truck is 60% longer than the car.<br><br> How long is the truck

ahrayia [7]

Answer:

250.8 is the answer

8 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

so

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

so

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago

Lines n and m are parallel and lines s and t are parallel, as shown.

bekas [8.4K]

Answer:

60

Step-by-step explanation:

straight lines are 180

since all lines are parallel

180 - 120 = 60

6 0

3 years ago

Read 2 more answers