[/tex]
This changes to a mix fraction
3 [tex] \frac{5}{9}
Answer:
f(2) = -6
General Formulas and Concepts:
Order of Operations: BPEMDAS
Substitution and Evaluation
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = -2x² + 4x - 6
f(2) is x = 2
<u>Step 2: Solve</u>
- Substitute: f(2) = -2(2)² + 4(2) - 6
- Exponents: f(2) = -2(4) + 4(2) - 6
- Multiply: f(2) = -8 + 8 - 6
- Add: f(2) = -6
Answer:
{3¢, 28¢} or {4¢, 19¢} or {7¢, 10¢}
Step-by-step explanation:
54 = 1×54 = 2×27 = 3×18 = 6×9
Possible values of the stamps are 1 more than the values of a pair of factors. Of course, a 2¢ and 55¢ stamp will not permit paying 54¢ in postage, so that combination won't work. However, other pairs that will work are ...
- 3¢ and 28¢
- 4¢ and 19¢
- 7¢ and 10¢
Answer:
-3x^6 -x^4 +2x^3 -8x +8
Step-by-step explanation:
Use the distributive property 4 times.
(-3x^3 + 2x - 4)×(x^3 + x - 2)
= -3x^3(x^3 +x -2) +2x(x^3 +x -2) -4(x^3 +x -2) . . . . once
= -3x^6 -3x^4 +6x^3 +2x^4 +2x^2 -4x -4x^3 -4x +8 . . . . 3 more times
= -3x^6 +x^4(-3+2) +x^3(6 -4) +2x^2 +x(-4 -4) +8 . . . . group like terms
= -3x^6 -x^4 +2x^3 -8x +8
Answer : B
the distance between the points (4,3) and (2,-1)
We apply distance formula
(x1,y1) is (4,3)
(x2,y2) is (2,1)
d^2 = 4+16 = 20
Take square root on both sides
So 
the distance between the points (4,3) and (2,-1) is 2sqrt(5)
