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liberstina [14]

2 years ago

8

Freddy has a bag of jellybeans which has the following colors to purple one red or yellow three orange what is the probability t

hat freddy will randomly selected purple jellybean eat it then select an orange jellybean

1 answer:

fgiga [73]2 years ago

8 0

Answer:

Because there are 3 purple and only one orange...

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AleksAgata [21]

2075-1195=880$ is the amount of increase

880/1195=0,74 now you only need to multiply with 100
0,74*100=74%
So the price increased by 74%

7 0

3 years ago

100 POINTS AND BRAINLIST

Tatiana [17]

Answer:

You can use the coordinates of a figure to find its dimensions by finding the distance between two points. To find the distance between two points with the same x-coordinates, subtract their y-coordinates. To find the distance between two points with the same y-coordinates, subtract their x-coordinates.

Step-by-step explanation:

6 0

2 years ago

Given TT = 3.142 the volume of the r = 4cm and h=8cm,Find the volume of the cone.

irakobra [83]

the volume of the cone.

1/3 pi r^2h

4 0

2 years ago

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Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

3 years ago

Round to the nearest tenth. 99.61

dusya [7]

99.60 or 100.00? I haven’t done this for a longgggg time

4 0

2 years ago

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