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2 years ago

(x+3)^2+4=46 what is the solution of this equation

Mathematics

2 answers:

lorasvet [3.4K]2 years ago

7 0

Step-by-step explanation:

(x + 3)² + 4 = 46

(x + 3)² = 42

x + 3 = ±sqrt(42)

x = ±sqrt(42) - 3

x1 = sqrt(42) - 3 = 3.480740698...

x2 = -sqrt(42) - 3 = -9.480740698...

I am Lyosha [343]2 years ago

4 0

Answer:

x = -3 + √42

Step-by-step explanation:

1) Expand the square

2) Distribute
3) Distribute

4) Distribute

5) Combine like terms

6) Add the numbers

7) Move terms to the left side

8) Subtract the numbers

9) Use the quadratic formula

10) Simplify

11) Separate the equations

12) Solve

Therefore, the solution of this equation is x = -3 + √42

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Read 2 more answers

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uysha [10]

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The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

$h(x)=ax(x-7)$ ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

$4=a(3)((3)-7)$

$4=a(3)(-4)$

$\dfrac{4}{(3)(-4)}=a$

$-\dfrac{1}{3}=a$

Putting $a=-\dfrac{1}{3}$ , we get

$h(x)=-\dfrac{1}{3}x(x-7)$ ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

$h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)$

$h(1.5)=-(0.5)(-5.5)$

$h(1.5)=2.75$

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

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3 years ago