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Gelneren [198K]
3 years ago
9

City code says you need to have a total of at least 54 toilet stalls, but each bathroom can only have 6 stalls. How many bathroo

m with 6 stall each must you build?
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

City code says you need to have a total of at least 54 toilet stalls, but each bathroom can only have 6 stalls.

So, Let the number of bathrooms to be built be = x

Number of toilet stalls needed = 54

Number of stalls each bathroom can have = 6

So, the number of bathrooms to be built are =

6(x)=54

x=\frac{54}{6}

x=9

Hence, one must build 9 bathrooms with 6 stalls each.

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Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
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The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

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Second term=40*2^{2-1}

=40*2^{1}

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Third term=40*2^{3-1}

=40*2^{2}

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Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

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