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SSSSS [86.1K]
2 years ago
7

The robotics club has created 10 racing robots for the end of year science fair. each robot has the same chance of winning the r

ace. what are the chances that robot a and robot b finish in the top three spots, but robot c is not in the top three?
Mathematics
1 answer:
Andreas93 [3]2 years ago
8 0

Answer:  \frac{7}{120}

Step-by-step explanation:

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Given line AB and point O on that line, any ray that can be drawn with its endpoint at O can be put into a one- to-one correspon
natima [27]

Answer:

Protractor

Step-by-step explanation:

A POSTULATE, LAW OR THEORY SHOULD NEVER BE ALTERED

∴ The protractor postulate states that the measurement of an angle between two rays can be designated as a unique number, and this number would be between 0 and 180 degrees, Hence for every angle A, there corresponds a positive real number less than or equal to 180. This postulate guarantee the use of a protractor to measure angles.

Hence, Given line AB and point O on that line in such a way that any ray that can be drawn with its endpoint at O can be put into a one- to-one correspondence with the real numbers between 0 and 180 is a statement that explains Protractor's Postulate.

4 0
3 years ago
Priya said, “It takes more cubes with edge length ⅖ inch than cubes with edge length ⅕ inch to pack the prism.” Do you agree wit
Lyrx [107]

V=A times B times C  that is the eqatuion

6 0
3 years ago
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
1 year ago
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