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2 years ago

11

Your deposit $1000 in an account that earns 2.5% annual interest. Find the balance after 2 years if the interest compounds with

the given frequency.

1 answer:

BaLLatris [955]2 years ago

8 0

Answer:

34%

Step-by-step explanation:

3+3+3+3+3+3+3+35%

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Write the point-slope equation for each line with the given slope and point. y –y1 = m(x – x1) Slope = 5 Point on line = (–1, 3)

snow_lady [41]

Answer:

$y-3=5(x+1)$

Step-by-step explanation:

Point-Slope form is: $y-y_1=m(x-x_1)$

'm' - Slope

(x1, y1) - Point Coordinate

We are given the point of (-1,3) and the slope of 5.

Replace 'm' with 5, 'x1' with -1, and 'y1' with 3:

$y-y_1=m(x-x_1)\rightarrow\boxed{y-3=5(x+1)}$

4 0

4 years ago

jack ran 1.5 kilometers on the treadmill, then walked 475 meters before running another 2.5 kilometers how many kilometers did j

qaws [65]

We need first consider what data we have available:
a = run 1.5km
b = then run 2.3km
c = walk 475m
x = a + b + c = how many km he done on treadmill
before we go anywhere, we need to unify the units, we need to change meters to fraction of kilometers, kilo meant 1000, therefore:
1km = 1000m
475m / 1000m = 0.475km
now we can substitute:
x = a + b + c = 1.5km + 2.3km + 0.475km = 4.275km
we can round that up to first decimal point and then:
4.275km = 4.3km
answer is then:
jack done on the treadmill 4.275km or rounded up 4.3km

3 0

3 years ago

Find the value of 15/4 divided by 5/8

dedylja [7]

Answer:

6

Step-by-step explanation:

15/4÷5/8

15/4×8/5

=6

3 0

3 years ago

Read 2 more answers

A long distance phone company charges a $2.95 monthly fee plus $0.14 for each minute write an algebraic expression to show the c

nataly862011 [7]

Answer:

2.95+0.14t=x

i think but ehhh, i am pretty sure about the constant but not to sure about the varibles

7 0

3 years ago

Read 2 more answers

The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).

Effectus [21]

Answer:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

Step-by-step explanation:

Given the quadratic equation as:

$2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0$

Let us put $sinx=y$ for simplicity of the equation:

Now, the equation becomes:

$2y^2+y-1=0$

Now, let us try to solve the quadratic equation:

$\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1$

So, the solution to the given trigonometric quadratic equation is:

$sinx = \dfrac{1}{2}$

and

$sinx=-1$

Let us try to find the values of $x$ in the interval $[0, 2\pi)$ .

$sin\theta$ can have a value equal to $\frac{1}{2}$ in 1st and 2nd quadrant.

So, $x$ can be

$30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}$

For $sinx=-1$ ,

$x = 270^\circ\ or\ \dfrac{3 \pi}{2}$

So, the answer is:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

7 0

3 years ago