Ask question

Ask question

All categories

2 years ago

12

HELP ASAP!! AND PLEASE EXPLAIN! The pyramid has a square base of 230 meters on each side and a height of 147 meters. Find the vo

lume of the pyramid if the slant height is 186.63 meters.

1 answer:

Mama L [17]2 years ago

7 0

Answer:

<u>2,592,100 m³</u>

Step-by-step explanation:

<u>Volume of Square Pyramid</u>

V = 1/3a²h
V = 1/3(230)²(147)
V = 49 x 52900
V = <u>2,592,100 m³</u>

You might be interested in

Write the equation of a line with a slope of 4 and a y-intercept of −3.

olga_2 [115]

Answer:

D. y = 4x − 3

Step-by-step explanation:

Just took the test and got 100%

7 0

2 years ago

Help me please im lost

Mashcka [7]

I’m sorry, but I’m also lost looking at that .

oh my

8 0

2 years ago

Read 2 more answers

If a 30-60-90 right triangle has a hypotenuse 6, what is the length of the short leg?

Anton [14]

Answer:

$\sqrt[3]{3}$

Step-by-step explanation:

use the Pythagoras Theorem

Since you have the hypotenuse (6"), just go backwards. 62 = 36 = a2 + b2.

6 0

2 years ago

The manager of a music store has kept records of

Marysya12 [62]

Answer:

(a) $P(x\le 3) = 0.75$

(b) $P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

(c) $P(x \ge 5) = 0.10$

(d) $P(x = 1\ or\ 2) = 0.55$

(e) $P(x > 2) = 0.45$

Step-by-step explanation:

Given

$\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

Solving (b): Probability of at most 3 CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x \ge 5) = P(5) + P(6\ or\ more)$

This gives:

$P(x\ge 5) = 0.05 + 0.05$

$P(x \ge 5) = 0.10$

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}$

This probability is calculated as:

$P(x = 1\ or\ 2) = P(1) + P(2)$

This gives:

$P(x = 1\ or\ 2) = 0.30 + 0.25$

$P(x = 1\ or\ 2) = 0.55$

Solving (e): Probability of more than 2 CDs

Here, we consider:

$\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)$

This gives:

$P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05$

$P(x > 2) = 0.45$

3 0

2 years ago

Ann runs a day care center. Of the last 18 children to enroll at the day care center, 8 of them have been elementary school stud

mrs_skeptik [129]

4 children i think. since you’re halving 18 you will half the 8 as well

4 0

3 years ago