Answer:
Now: 6 yr mean age
in 10 yrs? 16 yr mean age
in 20 yrs? 26 yr mean age
Why? Because regardless of the relationship between each sibling's age, your always adding the 10yrs to each individual, which you are then dividing out to determine the mean age. See proof below:
Including anita, there are 6 people. We'll define each age as an unknown variable. Assume we know nothing about the relationships between their ages
for example sake
anita's age = a
sister 1's age = b
sister 2's age = c
brother 1's age = d
brother 2's age = e
brother 3's age = f
Now:
mean age = (a + b + c + d + e + f)/(6 people) = 6 yrs
in 10 yrs:
mean age = ((a+10) + (b+10) + (c+10) + (d+10) + (e+10) + (f+10))/(6 people)
mean age = (a + b + c + d + e + f + 60)/(6 people)
mean age = (a + b + c + d + e + f)/(6 people) + (60)/(6 people)
mean age = (a + b + c + d + e + f)/(6 people) + 10
Notice the first term is the same expression of the mean age for "Now"
Thus, in 10 yrs:
mean age = 6 + 10 = 16 yrs
The same principle applies for "x" yrs from now, as long as we know what the mean age is "Now"
What about if you use the distributive property? You could do 1(x+13) because the 1 would distribute to the x and the 13 making it x+13. Hope that is helpful.
A rational number is a number that can be made by dividing 2 integers, such as 0.25 or 3/4.
An irrational number is a number that is not an imaginary number and cannot be expressed as a ratio between 2 integers. Basically, if an irrational number was written in a decimal notation, there would be an infinite amount of integers on the right side of the decimal. An example would be π (pi) or √2.
My solution to the problem is as follows:
sqrt(294) - sqrt(24) + sqrt(54)
= sqrt(49 * 6) - sqrt(4 * 6) + sqrt(9 * 6)
= sqrt(49)*sqrt(6) - sqrt(4)*sqrt(6) + sqrt(9)*sqrt(6)
= 7*sqrt(6) - 2*sqrt(6) + 3*sqrt(6)
= (7 - 2 + 3)*sqrt(6)
= 8*sqrt(6)
= sqrt(64)*sqrt(6)
<span>= sqrt(384)
= 8*sqrt(6)
Therefore, the answer is letter B, 8 square root of 6
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I hope my answer has come to your help. God bless and have a nice day ahead!
