What is the value of x?

Mathematics

1 answer:

Maurinko [17]3 years ago

5 0

Answer:

x=107 degree(being vertically oppostite angle)

Step-by-step explanation:

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7Dx%2B%20%5Cfrac%7B1%7D%7B2%7D%3D%20%5Cfrac%7B1%7D%7B4%7Dx-%20%5Cfrac%7B

zimovet [89]

$\dfrac{1}{4}x + \dfrac{1}{2} = \dfrac{1}{4}x- \dfrac{1}{2}$

$\text{Cancel 1/4x on both sides}$

$\dfrac{1}{2}=-\dfrac{1}{2}$

$\text{There is no solution}$

3 0

3 years ago

Read 2 more answers

Can someone help me in #66

VladimirAG [237]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------\\\\
$

$\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]$

$\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)$

6 0

3 years ago

Find 150% of 90 Please help me

maksim [4K]

Answer:

225

Step-by-step explanation:

mark me as brainliest pls i need it

7 0

2 years ago

Read 2 more answers

What is the equation of the circle with center (-3.2,-2.1) and the radius 4.3?

Nadya [2.5K]

If this makes sense lol... C = 2πr ≈ 2(3.14)(4.3) ≈ 27.02 m. An object travels in a circle of radius 4.3m at constant speed. It takes 1.4 seconds to go around once

5 0

3 years ago

Read 2 more answers

The science club is selling puzzles to raise money. The supplier charges a one-time fee of $55 for each order and $10 for each p

wariber [46]

I believe you can do 1,245 divided by 65 to find out how many puzzles they can buy I may be wrong :/

7 0

3 years ago