Let A = 40. If B is complement of A, and C is a supplmenet of B, what is B+C?
1 answer:
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Step-by-step explanation:
1.) Plug in one of the points.
y = 8x + b
6 = 8(4) + b
2.) Solve for b (or [?])
32 cancels out on the right side.
Subtract 32 from 6, which is -26
3.) -26 = b
4.) Check with other point:
-2 = 8(3) + b
-2 = 24 + b
Cancel out 24 on the right side: 24-24 = 0
-2 - 24 = -26
-26 = b
Answer:
Standard Deviation, σ = 6.5828058860438
Step-by-step explanation:
<u>Data Set:</u> 20, 11, 27, 13, 29, 20
The total numbers in the data set
Count, N = 6
The sum is all values in the data set is added up
20 + 11 + 27 + 13 + 29 + 20
Sum, Σx: 120
The mean is the sim / N
Mean, μ: 20
Answer:
The proportion of college students who work year-round is 58%.
Step-by-step explanation:
The claim made by the education researcher is that 58% of college students work year-round.
A random sample of 400 college students, 232 say they work year-round.
To test the researcher's claim use a one-proportion <em>z</em>-test.
The hypothesis can be defined as follows:
<em>H</em>₀: The proportion of college students who work year-round is 58%, i.e. <em>p</em> = 0.58.
<em>Hₐ</em>: The proportion of college students who work year-round is 58%, i.e. <em>p</em> ≠ 0.58. C
Compute the sample proportion as follows:
Compute the test statistic value as follows:
The test statistic value is 0.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected.
Compute the p-value for the two-tailed test as follows:
*Use a z-table for the probability.
The p-value of the test is 1.
The p-value of the test is very large when compared to the significance level.
The null hypothesis will not be rejected.
Thus, it can be concluded that the proportion of college students who work year-round is 58%.