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Rashid [163]
2 years ago
11

Find the four rational numbers between 2/3 and 5/6​

Mathematics
1 answer:
Sav [38]2 years ago
4 0

Answer:

Step-by-step explanation:

LCM of 3 and 6 = 6

2/3 = (2×2) / (3×2) = 4/6

4/6 = (4×5) / (6×5) = 20/30

5/6 = (5×5) / (6×5) = 25/30

Hence, 21/30, 22/30, 23/30 and 24/30 are four rational numbers between 2/3 and 5/6.

You might be interested in
7b + 3 – 4b = 3 – 3(b + 4)
svlad2 [7]

Hello from MrBillDoesMath!

Answer:  b

Discussion:

7b + 3 - 4b = 3 - 3(b+4)  =>

7b + 3 - 4b = 3 - 3b -12 =>

(7b - 4b) + 3   = -3b - 9 =>

3b + 3 = -3b -9    =>      Add 9 to both sides

3b + 12 = -3b -9 + 9  =>

3b + 12 = -3b  =>         ( add 3b to both sides)

6b + 12 = 0 =>             (subtract 12 from both sides)

6b = -12 =>

b = -12/6 = -2


Thank you,

MrB


7 0
3 years ago
What are the dimensions of the outside rectangle?
Inessa [10]

Outer Square perimeter minus inside perimeter equals outside square perimeter

5 0
3 years ago
Find the measures of the angles given
dexar [7]

Answer:

BCD = 60

ABD - 90

Step-by-step explanation:

BCD)

BC and CD are the same length on in the circle, they are the radius. Therefor,  all angles will be the same at 60

ABD)

All angles together are 180

You know 2 Angles, A at 30 and D at 60

180 - 30 - 60 = Angle B

90 = Angle B

6 0
3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
Parallel lines in real world, help please
e-lub [12.9K]

Answer:

The answer is B(65)

Step-by-step explanation:

you just do 180 - JCB  = 65

so you do 180-65=115

hope this helps

6 0
3 years ago
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