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3 years ago

A triangular prims cover with a fold label. the label dose not cover the 2 ends. how much foil is necessary to cover the prism.

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

I just took the test and I got it right but if you don't I'm so sorry :<

Temka [501]3 years ago

3 0

Just multiply it all together and that’s ur answer

You might be interested in

*trigonometry and area.*

soldier1979 [14.2K]

Answer:

<u>The correct answer is that the area of the regular octagon is 309 cm²</u>

Step-by-step explanation:

There are several formulas for calculating the area of a regular octagon. We will use this one for solving this question because it does not require additional information .

Area = (2 * s²)/tan 22,5°

s = 8 cm

Replacing with the real values, we have:

Area = (2 * 8²)/tan 22,5°

Area = 2 * 64/0.4142

Area = 128/0.4142

<u>Area = 309 cm² (Rounding to the nearest tenth)</u>

6 0

3 years ago

Helping my sister with her homework

zimovet [89]

Answer:

5 : 10

6 : 12

7 : 14

8 : 16

9 : 18

Step-by-step explanation:

10/5=2

there is only one number in between 7 and 5

so now you have to go up 2 each time in the right collum and go up once in the left collum.

6 0

3 years ago

4tan^2 x-8tanx+3=0 on interval [0,2pi]

Vadim26 [7]

$\bf 4tan^2(x)+8tan(x)+3=0\qquad [0,2\pi ]
\\\\\\
\textit{since it's just a quadratic, we'll just factor it}
\\\\\\\
[2tan(x)+1][2tan(x)+3]=0\implies 
\begin{cases}
2tan(x)+1=0\\
\qquad tan(x)=-\frac{1}{2}\\
\qquad \measuredangle x=tan^{-1}\left( -\frac{1}{2} \right)\\
\qquad \measuredangle x\approx 333.4^o, 153.4^o\\
2tan(x)+3=0\\
\qquad tan(x)=-\frac{3}{2}\\
\qquad \measuredangle x=tan^{-1}\left(-\frac{3}{2} \right)\\
\qquad \measuredangle x\approx303.7^o, 123.7^o
\end{cases}$

7 0

3 years ago

.5x−6=x+0.05 <br><br> Which number is equal to the value of x?

Daniel [21]

The answer to the question is x=-12.1hopes this helps you.

<span> Step 1: subtract X from both sides.

0.5x-6-x=x+0.05-x

-0.5x-6=0.05</span>
Step 2: Add 6 to both sides.

-0.5x-6+6=0.05+6

-0.5x=6.05
Step 3: Divide both sides by -0.5.−0.5x−0.5=6.05−0.5

7 0

3 years ago

X^2+4=square root 13

beks73 [17]

Answer:

$\large\boxed{x=-\sqrt{\sqrt{13}-4}}\ \vee\ x=\sqrt{\sqrt{13}-4}}$

Step-by-step explanation:

$x^2+4=\sqrt{13}\qquad\text{subtract 4 from both sides}\\\\x^2+4-4=\sqrt{13}-4\\\\x^2=\sqrt{13}-4\Rightarrow x=-\sqrt{\sqrt{13}-4}}\ \vee\ x=\sqrt{\sqrt{13}-4}$

5 0

3 years ago