Step-by-step explanation:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
I think it's D bc I looked it up in internet and it's what It gave me
Answer:
12
Step-by-step explanation:
I had the SAME EXACT question, IIT WAS right trust.
Simplify 2.8y + 6 + 0.2y to 3y + 6
subtract 3y from both sides
simplify 5y - 15 - 3y to 2y - 15
add 15 to both sides
simplify 6 + 15 to 21
divide both sides by 2
switch sides
Answer: y = 21/2
*in decimal form this would be 10.5
(15*-3)-12
3(with another mini three)+4=?
