True:
3rd One
4th One
False: All of the others.
It's a straight line, so it is going to have straight qualities and straight inequalities throughout the graph.
They won 20/30, so 100 / 30 = 3.3, then times by 20 = 66.66.
Hope this helps.
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
A
Step-by-step explanation:
that's the right answer
