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3 years ago

Which nucleotides pair together in DNA?

Chemistry

2 answers:

tensa zangetsu [6.8K]3 years ago

7 0

Answer:

adenine (A) and thymine (T) pair together and cytosine (C) and guanine (G) pair together in DNA

hram777 [196]3 years ago

3 0

Under normal circumstances, the nitrogen-containing bases adenine (A) and thymine (T) pair together, and cytosine (C) and guanine (G) pair together. The binding of these base pairs forms the structure of DNA

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How many moles of H2 would be contained in 4.0 L of the gas at 202.6 kPa and 127°C?

kicyunya [14]

Use PV =nRT. Rearrange it to n = PV/RT.
P = 202.6 kPa
V = 4.0L
R = 8.314 kPa*L/mol*K
T = 127 °C + 273 = 400 K
Plug it in and solve. I got 0.24 moles of H2.

6 0

4 years ago

Read 2 more answers

Using the appropriate Ksp values, find the concentration of K+ ions in the solution at equilibrium after 600 mL of 0.45 M aqueou

Alekssandra [29.7K]

Answer:

[K⁺] = 0.107 M

[OH⁻] = 1.13 × 10⁻⁹ M

Explanation:

600 mL of 0.45 M Cu(NO3)2 gives equal mole of Cu²⁺ and (NO₃)²⁻

⇒ 0.45 × 600 × 10⁻³

= 0.27 moles of Cu²⁺ and (NO₃)²⁻

450 mL of 0.25 M KOH gives equal moles of K⁺ and OH⁻

⇒ 0.25 × 450 × 10⁻³

= 0.1125 moles of K⁺ and OH⁻

Now after mixing 0.1125 moles of OH⁻ precipitates 0.05625 moles of Cu²⁺ (because 1 Cu²⁺ needs 2 OH⁻)

Therefore , moles of remaining Cu²⁺ = 0.27 - 0.05625

=0.21375 moles which is equal to :

⇒ 0.21375/(( 600+450))× 10⁻³

= 0.21375/1050 × 10⁻³

= 0.20357 M

Given that :

(Ksp for Cu(OH)2 is 2.6 × 10⁻¹⁹)

We know that , Ksp = [Cu²⁺][OH⁻]²

2.6 × 10⁻¹⁹ = 0.20357 × [OH⁻]²

[OH⁻]² = 2.6 × 10⁻¹⁹/0.20357

[OH⁻] = 1.13 × 10⁻⁹ M

[K⁺] = moles of K⁺ /total volume

[K⁺] = 0.1125 / 1050 × 10⁻³

[K⁺] = 0.107 M

6 0

3 years ago

A 20g sample of iron at a temperature of 120oC is placed into a container of water. There are 300 milliliters of water in the co

galben [10]

Answer:

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of iron = $m_1=20 g$

Specific heat capacity of iron = $c_1=0.444 J/g^oC$

Initial temperature of the iron = $T_1=120^oC$

Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

Volume of water = 300 ml

Density of water = 1 g/mL

Mass of water= $m_2=300 mL\times 1 g/mL = 300 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=30^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

we get, T = 30.63°C

30.63 °C will be the final temperature of the water.

4 0

3 years ago

Why Sodium and phosphorus are in the same period, but they have different atomic radii?

Marianna [84]

Answer:

Because sodium is on the left side of the PT and phosporus is on the right side. And atomis radius decreases from left to right.

Explanation:

4 0

3 years ago

Please please help me solve this, I have a test and only 20 mins left T-T<br>

Ann [662]

Answer: $5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is:
[tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)$

According to stoichiometry :

2 moles of $NH_4NO_3$ produce = 4 moles of $NO_2$ gas and 1 mole of $O_2$ gas

2 moles of $NH_4NO_3$ produce = 5 moles of gas

Thus 0.1 mole of $NH_4NO_3$ produce = $\frac{5}{2}\times 0.1=0.25moles$ of gas

Volume of gas produced = $moles\times {\text {Molar volume}}=0.25moles\times 22.4dm^3/mol=5.6dm^3$

Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.

7 0

3 years ago