Question

How many molecules are in 100. l of potassium hydroxide solution at stp?

Answer 1

Answer : There are $2.68\times 10^{24} molecules$ in 100 Lof potassium hydroxide(KOH) solution at stp.

Explanation : To calculate the molecules we first need to find out the moles.

One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).

1 mole = 22.4 L

100 L = $(100 L)\times \frac{(1mole)}{(22.4 L)}$

100 L = $(100)\times \frac{(1mole)}{(22.4)}$

100 L = 4.46 mole potassium hydroxide(KOH)

Now , we need to convert 4.46 mole to molecules of KOH.

$1 mole = 6.02\times 10^{23} molecules$

4.46 moles = $(4.46 mole)\times \frac{(6.02\times 10^{23}molecules)}{(1 mole)}$

4.46 moles = $(4.46)\times \frac{(6.02\times 10^{23}molecules)}{(1 )}$

4.46 moles = $2.68\times 10^{24} molecules$

There are $2.68\times 10^{24} molecules$ in 100 Lof potassium hydroxide(KOH) solution at STP.