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Irina-Kira [14]
3 years ago
8

3- Um tipo de nutriente complexo presente

Chemistry
1 answer:
umka21 [38]3 years ago
4 0

Answer:

The human body when metabolizing meat, milk or eggs, being high in protein, manufactures uric acid as a metabolite, and releases more urea in the urine.

Uric acid generates an increased retention of liquid or water, that is why people who ingest excessively meat suffer from GOTA disease.

Gout disease is systemic and life-threatening puffiness.

Furthermore uric acid is an organic compound of carbon, nitrogen, oxygen and hydrogen. Its chemical formula is C5H4N4O3. It is found in urine in small amounts.

And urea is defined as a renal parameter from the quantitative point of view; It is a colorless, crystalline chemical compound of formula CO (NH2) 2. It is found abundantly in urine and faeces.

Explanation:

To have an accurate idea of the function of the kidneys, it is sufficient to carry out a simple blood test with determination of Urea and creatinine and an analysis of a urine sample in which the presence of cells (red blood cells and leukocytes) is assessed. and / or proteins (albumin). Today these 2 types of analysis are part of the routine of any analytical study.

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2.) In a series of experiments, a chemist prepared three different compounds that contain only iodine and fluorine. He then dete
kaheart [24]

Answer:

compound 1 = 0.749gF / 1.0gl

compound 2 = 0.4489gF / 1.0gl

compound 3 = 1.047gF / 1.0gl

Explanation:

Given that;

compound       mass of iodine in grams          mass of fluorine in grams

       1                              4.75                                             3.56

       2                             7.64                                             3.43

       3                             9.41                                              9.86

a) Calculate the mass of fluorine per gram of iodine in each compound:

- compound 1

mass of Fluorine = (3.56gF / 4.75gF) * 1.0gl

= 0.749gF

Now RATIO = 0.749gF / 1.0gl

- compound 2

mass of Fluorine = (3.43gF / 7.64gF) * 1.0gl

= 0.4489gF

Now RATIO = 0.4489gF / 1.0gl

- compound 3

mass of Fluorine = (9.86gF / 9.41gF) * 1.0gl

= 1.047gF

Now RATIO = 1.047gF / 1.0gl

8 0
3 years ago
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