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A. Area of given figure = 280 + 77 = 357 cm²
B. length of semicircle = 22 cm
Answer:
Step-by-step explanation:

Answer:
A
Step-by-step explanation:
b is the range
I think the answer to the expression would be D. (10 - 2) x 4 because (10 - 2) would be multiplied 4 times, which means it would be four times greater. I hope this made sense and also helped you in some way.
Answer:
can't understand the question
Step-by-step explanation:
have a good day!