All categories

3 years ago

17 *2477 using long division

Mathematics

1 answer:

Kazeer [188]3 years ago

5 0

Answer:

42109

Step-by-step explanation:

(17*7)+(17*70)+(17*400)+(17*2000)=119+1190+6800+34000=42109

You might be interested in

Solve 5ax + 3ax = 4ax + 12 for x. Assume a ≠ 0

eduard

8ax=4ax+12

4ax=12

x=3/a

Hope it helps! Comment if you have any questions!

7 0

3 years ago

Read 2 more answers

Given the function f(x) = 2x-5 and g(x), which function has a greater slope?

adell [148]

Answer:

g(x) has a greater slope

Step-by-step explanation:

step 1

Find the slope of f(x)

we have

$f(x)=2x-5$

This is a linear function in slope intercept form

$f(x)=mx+b$

where

m is the slope

b is the y-intercept

$m=2$

step 2

Find the slope of g(x)

take two points from the table

(2,0) and (4,5)

$m=(5-0)/(4-2)\\m=5/2=2.5$

step 3

Compare the slopes

$2.5 > 2$

The slope of g(x) is greater than the slope of f(x)

3 0

4 years ago

In parallelogram ABCD, what is m

Basile [38]

9514 1404 393

Answer:

(d) 25°

Step-by-step explanation:

Each diagonal represents a transversal between parallel lines. Alternate interior angles are congruent, so ...

∠BDC ≅ ∠DBA = 25°

7 0

3 years ago

Twice a number decreased by 20 is 50. What is that number

castortr0y [4]

2(n-20)=50
n-20=25

n=45

8 0

3 years ago

Read 2 more answers

suppose for an angle theta in a right triangle cos theta = C. Sketch and label this triangle, and then use it to write the other

VARVARA [1.3K]

Answer:

$sin\theta = \sqrt{1-C^2}$

$tan\theta = \dfrac{\sqrt{1-C^2}}{C}$

$cot\theta = \dfrac{C}{\sqrt{1-C^2}}$

$sec\theta = \dfrac{1}{C}}$

$cosec\theta = \dfrac{1}{\sqrt{1-C^2}}$

Step-by-step explanation:

Given that:

$\theta$ is an angle in a right angled triangle.

and $cos\theta = C$

To find:

To draw the triangle and write other five trigonometric functions in terms of C.

Solution:

We know that cosine of an angle is given by the formula:

$cosx =\dfrac{Base}{Hypotenuse}$

Here, we are given that $cos\theta = C$ OR

$cos\theta = \dfrac{C}{1}$

i.e. Base = C and Hypotenuse of triangle = 1

Please refer to the right angled triangle as per given statements.

$\triangle PQR$ , with base PR = C units

and hypotenuse, QP = 1 unit

$\angle R$ is the right angle.

Let us use pythagorean theorem to find the value of perpendicular.

According to pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}$

$1^{2} = C^{2} + QR^{2}\\\Rightarrow QR = \sqrt {1-C^2}$

$sin\theta = \dfrac{Perpendicular}{Hypotenuse}\\\Rightarrow sin\theta = \dfrac{\sqrt{1-C^2}}{1}\\\Rightarrow sin\theta = \sqrt{1-C^2}$

$tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan\theta = \dfrac{\sqrt{1-C^2}}{C}$

$cot\theta = \dfrac{Base}{Perpendicular}\\\Rightarrow cot\theta = \dfrac{C}{\sqrt{1-C^2}}$

$sec\theta = \dfrac{Hypotenuse}{Base}\\\Rightarrow sec\theta = \dfrac{1}{C}}$

$cosec\theta = \dfrac{Hypotenuse}{Perpendicular}\\\Rightarrow cosec\theta = \dfrac{1}{\sqrt{1-C^2}}$

5 0

3 years ago