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muminat
3 years ago
9

17 *2477 using long division

Mathematics
1 answer:
Kazeer [188]3 years ago
5 0

Answer:

42109

Step-by-step explanation:

(17*7)+(17*70)+(17*400)+(17*2000)=119+1190+6800+34000=42109

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Solve 5ax + 3ax = 4ax + 12 for x. Assume a ≠ 0
eduard

8ax=4ax+12

4ax=12

x=3/a

Hope it helps! Comment if you have any questions!

7 0
3 years ago
Read 2 more answers
Given the function f(x) = 2x-5 and g(x), which function has a greater slope?​
adell [148]

Answer:

g(x) has a greater slope

Step-by-step explanation:

step 1

Find the slope of f(x)

we have

f(x)=2x-5

This is a linear function in slope intercept form

f(x)=mx+b

where

m is the slope

b is the y-intercept

so

m=2

step 2

Find the slope of g(x)

take two points from the table

(2,0) and (4,5)

m=(5-0)/(4-2)\\m=5/2=2.5

step 3

Compare the slopes

2.5 > 2

so

The slope of g(x) is greater than the slope of f(x)

3 0
4 years ago
In parallelogram ABCD, what is m
Basile [38]

9514 1404 393

Answer:

  (d)  25°

Step-by-step explanation:

Each diagonal represents a transversal between parallel lines. Alternate interior angles are congruent, so ...

  ∠BDC ≅ ∠DBA = 25°

7 0
3 years ago
Twice a number decreased by 20 is 50. What is that number
castortr0y [4]
2(n-20)=50
n-20=25

n=45
8 0
3 years ago
Read 2 more answers
suppose for an angle theta in a right triangle cos theta = C. Sketch and label this triangle, and then use it to write the other
VARVARA [1.3K]

Answer:

sin\theta = \sqrt{1-C^2}

tan\theta = \dfrac{\sqrt{1-C^2}}{C}

cot\theta = \dfrac{C}{\sqrt{1-C^2}}

sec\theta = \dfrac{1}{C}}

cosec\theta = \dfrac{1}{\sqrt{1-C^2}}

Step-by-step explanation:

Given that:

\theta is an angle in a right angled triangle.

and cos\theta = C

To find:

To draw the triangle and write other five trigonometric functions in terms of C.

Solution:

We know that cosine of an angle is given by the formula:

cosx =\dfrac{Base}{Hypotenuse}

Here, we are given that cos\theta = C OR

cos\theta = \dfrac{C}{1}

i.e. Base = C and Hypotenuse of triangle = 1

Please refer to the right angled triangle as per given statements.

\triangle PQR, with base PR = C units

and hypotenuse, QP = 1 unit

\angle R is the right angle.

Let us use pythagorean theorem to find the value of perpendicular.

According to pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

1^{2} = C^{2} + QR^{2}\\\Rightarrow QR = \sqrt {1-C^2}

sin\theta = \dfrac{Perpendicular}{Hypotenuse}\\\Rightarrow sin\theta = \dfrac{\sqrt{1-C^2}}{1}\\\Rightarrow sin\theta = \sqrt{1-C^2}

tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan\theta = \dfrac{\sqrt{1-C^2}}{C}

cot\theta = \dfrac{Base}{Perpendicular}\\\Rightarrow cot\theta = \dfrac{C}{\sqrt{1-C^2}}

sec\theta = \dfrac{Hypotenuse}{Base}\\\Rightarrow sec\theta = \dfrac{1}{C}}

cosec\theta = \dfrac{Hypotenuse}{Perpendicular}\\\Rightarrow cosec\theta = \dfrac{1}{\sqrt{1-C^2}}

5 0
3 years ago
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