Find each probability if you pick to marble without replacing the first (G=green; R=red; Y=yellow).

i will give u brainlyist plz When 1/3 is written as a repeating decimal, which digits are repeating? A. 27 B. 37 C. 73 D. 28

gogolik [260]

Answer:

1/3 in decimal format is .333333333333... so none of these are correct

7 0

2 years ago

7. The following clues are given about a bucket of bubble gum.

scZoUnD [109]

There were 472 pieces of bubble gum in the bucket

Step-by-step explanation:

The following clues are given about a bucket of bubble gum

1. There are between 400 - 500 pieces of gum in the bucket

2. The bubble gum was purchased in 4 equally-sized bags

3. The product of all the digits is 56

Let us explain how to solve the problem

∵ The number of the pieces of gum is between 400 and 500

∴ The number of pieces is 3-digit number and its hundred digit is 4

∵ The product of all digits is 56

∵ One of the digit is 4

∵ 56 ÷ 4 = 14

∴ The product of the ten digit and the one digit is 14

∵ 14 = 2 × 7

∴ The ten digit and the one digit are 2 and 7 or 7 and 2

- If the ten digit is 2 and the one digit is 7

∴ The number of pieces is 427

∵ The bubble gum was purchased in 4 equally-sized bags

- That means there were 4 pieces of bubble gum in each bag

∴ The number of pieces must divisible by 4

- The number is divisible by 4 if it is an even number and the number

formed from the ten digit and one digit is divisible by 4

∵ 427 is an odd number

∴ 427 not divisible by 4

- If the ten digit is 7 and the one digit is 2

∴ The number of pieces is 472

∵ 472 is an even number

∵ 72 divisible by 4

∴ 472 is divisible by 4

∴ There are 472 pieces of gum in the bucket

There were 472 pieces of bubble gum in the bucket

Learn more:

You can learn more about digits in brainly.com/question/547255

#LearnwithBrainly

7 0

3 years ago

Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

2 years ago

Jillian measured the distance around a small fish pond as 27 yards. Which would be a good estimate for the distance across the p

DochEvi [55]

Assuming the fish pond is round, what you're given is the circumference.
So you know that 2<span>πr = 27.
We want to solve for the diameter, or d = 2r. We should isolate that.
2r = 27/</span><span>π
2r = 8.59 yards, or ~9 yards.</span>

3 0

2 years ago

Eggs are sold in boxes. A small box holds 6 eggs.A large box holds 12 eggs.Hina buys x small boxes of eggs.Hina also buys 4 less

yuradex [85]

Answer:

a) 12x - 48 or 6(2x - 8)

b) 18x - 48 or 6(3x - 8)

Step-by-step explanation:

A small box holds 6 eggs

A large box holds 12 eggs.

Hina buys x small box of eggs

Hina also buys (x-4) large box of eggs

a) Total number of eggs in the large box by Hina = (x-4)12

= 12x - 48

= 6(2x - 8)

b) Total number of eggs bought by Hina = (x) 6 + (x-4)12

= 6x + 12x - 48

= 18x - 48

= 6(3x - 8)

8 0

3 years ago