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BARSIC [14]
2 years ago
9

Emily has a road map with a key that shows an inch on the map equals 3 miles of actual distance. She will drive on two roads to

get to the beach. One road is 4 inches long on the map. The other road is 4 inches long.
What is the actual distance Emily will drive to the beach? Complete the rule you used to find the actual distance.
Mathematics
1 answer:
77julia77 [94]2 years ago
4 0

Answer:x=60

Step-by-step explanation:

the actual distance which Emily will drive is 60 miles, the rule we used was multiplying by 5 to find the actual distance

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Select the correct answer
bulgar [2K]
The answer is b bc it’s all real numbers since it won’t stop
3 0
3 years ago
I’m confused can ya help me
Harlamova29_29 [7]

Answer:

C & D

Step-by-step explanation:

x² + 3x - 3 = 0

a = co efficient of  x² = 1

b=  co efficient of x = 3

c = constant = -3

roots = (-b ± \sqrt{b-4ac})/2a

    = (-3±\sqrt{3^{2}-4*1*[-3]} )/2*1

    = (-3±\sqrt{9+12})/2

    = (-3±√21)/2

  x = \frac{-3+\sqrt{21}}{2}     ; x =\frac{-3-\sqrt{21}}{2}

7 0
3 years ago
5 plus the difference of 9 and 4
irakobra [83]
So first, you subtract 9 and 4, which gives you 5. Then, you add that to 5. That gives you 10.
6 0
3 years ago
Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
8 0
3 years ago
Which mixed number is greater 5 7/24 or 5 5/16
Sauron [17]
5 5/16 is greater.
You can find that out by dividing 5/16 and 7/24
So that gives .31 and .29
Thus, 5 5/16 are greater
3 0
3 years ago
Read 2 more answers
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