Ttthe said she had no reason why he would be able answer that he had been in ,.....
Answer:
7.2 units
Step-by-step explanation:
Coordinates of city A = (0, 0)
Coordinates of city B = (6, 4)
Use the distance formula to find the distance between the two cities as follows:

Let,


Plug in the values into the formula



(nearest tenth)
The union of a collection of sets is the set of all elements in the collection.
We have B = {a, l, g, e, b, r} and C = {m, y, t, h}
<h3>B ∪ C = {a, l, g, e, b, r, m, y, t, h}</h3>
Answer:

<h3>
♁ Question : Solve for x</h3>
<h3>♁ Step - by - step explanation</h3>
Move 12x to L.H.S ( Left Hand Side ) and change it's sign
➛
Move 7 to R.H.S ( Right Hand Side) and change it's sign
➛
Subtract 12x from 15x
Remember that only coefficients of like terms can be added or subtracted.
➛
Add the numbers : 2 and 7
➛
Divide both sides by 3
➛ 
➛ 
The value of x is 
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☄ Now, let's check whether the value of x is 3 or not!
<h3>
☥ Verification :</h3>




L.H.S = R.H.S ( Hence , the value of x is 3 ).
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<h3>✒ Rules for solving an equation :</h3>
- If an equation contains fractions ,multiply each term by the L.C.M of denominators.
- Remove the brackets , if any.
- Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
- Simplify and get the single term on each side.
- Divide each side by the coefficient of variable and then get the value of variable.
Hope I helped!
Have a wonderful time ! ツ
~TheAnimeGirl