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Leni [432]
1 year ago
5

Agroup of friends were working on a student film with a budget of $500, which they

Mathematics
2 answers:
Svet_ta [14]1 year ago
6 0

$500- $55= $445

445/500 = 89/100

89/100 × 100/1= 89%

Answer: 89%

mina [271]1 year ago
4 0

Answer:

89%

Step-by-step explanation:

500-55=445

445/500=0.89

0.89x100=89

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Is this true? And also how does the equation from y-3=3(x-4) become a positive <br> y+3=3x-12?
EastWind [94]

Step-by-step explanation:

the right equation is :

y-y1=m(x-x1)

y+3=3(x+4)

y+3= 3x+12

y=3x+12-3

y=3x+9

7 0
2 years ago
What is the answer to this equation<br> g + 5 = 16<br> g=?
stiv31 [10]

Answer:

G=11

Step-by-step explanation:

g+5=16

You need to get rid of the 5, so take away 5 from both sides.

16-5=11

g=11

7 0
3 years ago
Read 2 more answers
Solve the problem.
scoundrel [369]

Answer:

Step-by-step explanation:

7 0
3 years ago
ANSWER ASAP GIVING BRAILIEST AND STUFF!
natita [175]

Answer:

24s^2, 54s^2, 96s^2

Step-by-step explanation:

Let s represent the initial side length of the cube.  Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).

a) Now suppose we double the side length.  The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),

b) tripled:  A = 6(3s)^2 = 54x^2

c) quadrupled?  A = 6(4s)^2 = 96s^2

6 0
3 years ago
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo
kolezko [41]

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2<em>x</em> + <em>y</em> = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

<em>x</em> + 3<em>y</em> = 0.25

Solve for <em>x</em> and <em>y</em>. We have

<em>y</em> = 0.25 - 2<em>x</em>   ==>   <em>x</em> + 3 (0.25 - 2<em>x</em>) = 0.25

==>   <em>x</em> + 0.75 - 6<em>x</em> = 0.25

==>   5<em>x</em> = 0.5

==>   <em>x</em> = 0.1

==>   <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4<em>x</em> + 4<em>y</em> = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time <em>t</em> to fill one pool, we have

(3/5 pool/hour) (<em>t</em> hours) = 1 pool

==>   <em>t</em> = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0
3 years ago
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