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3 years ago

12

Hello please help thanks i’ll give brainliest!

1 answer:

erastovalidia [21]3 years ago

8 0

Answer: A

Step-by-step explanation: Hope this help :D

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Find the area of the figure below

alex41 [277]

Answer: 29

Step-by-step explanatio?

3 0

3 years ago

Sierra has enough fencing to make three chicken coops shown each has the same perimeter which has the greatest area?

andrezito [222]

Answer:

Top left triangle has the greatest area

Step-by-step explanation:

Area of a triangle:

area = base × height / 2

a = bh/2

Top Left Triangle:

a = 6 × 5.2 / 2

a = 31.2 / 2

a = 15.6

Top Right Triangle:

a = 8 × 2.9 / 2

a = 23.2 / 2

a = 11.6

Bottom Left Triangle:

a = 2 × 7.9 / 2

a = 15.8 / 2

a = 7.9

Compare areas:

15.6 > 11.6 > 7.9

4 0

3 years ago

For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

(c) Margin of error ( E) = $500

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

3 years ago

I need some help please out

IceJOKER [234]

Question:

Solution:

Let the following equation:

$\sqrt[]{12-x}=\text{ x}$

this is equivalent to:

$(\sqrt[]{12-x})^2=x^2$

this is equivalent to:

$12-x=x^2$

this is equivalent to:

$x^2+x-12=\text{ 0}$

thus, we can conclude that

x= 3.

7 0

1 year ago

How will adding the value 90 affect the mean and median of the data set 1, 5, 5, 6, 9, 10?

Soloha48 [4]

I believe the answer is B for this question

6 0

3 years ago

Read 2 more answers