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Nesterboy [21]
3 years ago
12

Hello please help thanks i’ll give brainliest!

Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0

Answer: A

Step-by-step explanation: Hope this help :D

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What is "twenty-six thousandths" in decimal form?
aniked [119]

Answer:

twenty-six thousandths in decimal form is "0.0026"

Hope this helped

Step-by-step explanation:

7 0
3 years ago
DO THIS FAST PLEASE I WILL GIVE BRAINLY CROWN
vekshin1

5 ÷ 1/2 => 5 x 2/1 => 10/1 => 10

8 0
3 years ago
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What is the 57th term of the arithmetic sequence : 11,8,5,2
andriy [413]
I think its this <span> 14 - 3*57 = 14 - 171 = -157 </span>
4 0
3 years ago
Which ordered pair is a solution of the equation? y = 7 x − 3 y=7x−3
eimsori [14]

Answer:

(1,4)

Step-by-step explanation:

Which ordered pair is a solution of the equation? y = 7 x − 3

a. (1,4) b. (-1,-4) c. both d. neither

Solution

y=7x-3

Solve by trying each ordered pair

a. (1,4)

x=1, y=4

Substituting the value of x and y into the equation

y=7x-3

4=7(1)-3

4=7-3

4=4

This is a true statement

b. (-1,-4)

x=-1, y=-4

Substitute the value into the equation

y=7x-3

-4=7(-1)-3

-4= -7-3

-4= -11

This is not a true statement

This true statement is when x=1 and y=4

So, the ordered pair (1, 4) is the solution

8 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
3 years ago
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