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3 years ago

The value of the digit in the hundreds place is _ time as great as the digit in the tenths I need to find out the blank

Mathematics

2 answers:

Gala2k [10]3 years ago

7 0

This will be 100/10 = 10 times the value

stira [4]3 years ago

3 0

it is 10 times greater

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Classify each angle.

serg [7]

Answer:

∠MDP = 90° = Right angle

∠MDP = 180° = Straight angle

∠ODM = 90° = Right angle

∠OND = Not an angle

∠NDO = 90° = Right angle

∠NDM = 180° = Straight angle

∠PMN = Not an angle

∠PDO = 180° = Straight angle

∠PDN = 90° = Right angle

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3 years ago

If ax+b=3 and a=0, then x=

Harrizon [31]

Answer:

3 it is 3

Step-by-step explanation:

3+0=3

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3 years ago

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Add −1.25+2.5 Plot the first addend and the sum on the number. Please tell the explain

Assoli18 [71]

If signs are different you subtract. So 2.5- -1.25 equals 1.25 and keep the sign of the biggest number

7 0

2 years ago

A student has 10 coins in her pocket that have a value of $0.85. The coins are either

il63 [147K]

Answer:

$\left\{\begin{matrix}x+y=10\\ 0.05x+0.10y=0.85\end{matrix}\right.$

Step-by-step explanation:

System of Equations

Let's call:

x = number of nickels in the student's pocket

y = number of dimes in the student's pocket

Each nickel has a value of $0.05, so x nickels have a value of 0.05x

Each dime has a value of $0.10, so y dimes have a value of 0.10y

The student has a total of 10 coins, thus:

$x+y=10$

The total value of the coins is $0.85, thus

$0.05x+0.10y=0.85$

The system of linear equations that represents this scenario is:

$\left\{\begin{matrix}x+y=10\\ 0.05x+0.10y=0.85\end{matrix}\right.$

5 0

2 years ago

Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

2 years ago