Answer:
The answer is choice 2 and 3, that is "The quotient has a final decimal and the whole number is less than 11".
Step-by-step explanation:
The product of a ratio: amount (r) over other(s) (variance from 0) becomes mandatory to note this quotient and in the following case Thus q is = 0.0882352941.

It wasn't a repeating decimal, however a final decimal, so it's got an end.
Its quotient may be less than 11 in total.
Numbers of W = {0,1,2, ...} and 0 < 11 are provided for this entire series of data therefore It's real .
Answer:

Step-by-step explanation:
The diagram of the problem is drawn and attached.
Given that:



Also

y -3 = 2(x-4)
Use distributive property on the right side:
y - 3 = 2x -8
Add 3 to both sides:
y = 2x -5
The answer is A.
Given:
The equation is:

To find:
The graph of the line that contains ordered pairs that are solutions of the given equation.
Solution:
We need to find the graph of the given equation.
We have,

At
, we get


So, the x-intercept of the given equation is at point (0,4).
At
, we get


So, the y-intercept of the given equation is at point (4,0).
From the given graphs it is clear that the line in option C has x-intercept at point (0,4) and y-intercept at point (4,0).
Therefore, the correct option is C.
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