3. Which point is located at (4, -5)?А в с D

Mathematics

2 answers:

katen-ka-za [31]2 years ago

8 0

Answer:

Your answer to this question is C (4, -5)

tatyana61 [14]2 years ago

5 0

Answer:

Point C is located at (4, -5)

Step-by-step explanation:

Hope it helps

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Solve for x. Show your work. 1 x<-12 2

Airida [17]

Answer:

2 is not a solution

Step-by-step explanation:

x < -12

Step 1: Check if 2 is less than -12

2 < -12

No, this doesn't work

Answer: 2 is not a solution

5 0

3 years ago

15/16 divided by 3/4 = ?

Dmitry [639]

5/4

(15/16)(4/3) The 4/3 is the reciprocal of 3/4

=5/4

8 0

3 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

Solution:

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$