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3 years ago

Part A- What is the discount rate at the store closing?

Mathematics

2 answers:

Andreas93 [3]3 years ago

8 0

1 question I believe it’s A. 2 question I believe it’s C. 3 question I believe it’s B. Hope this help❤️.

MatroZZZ [7]3 years ago

6 0

Answer:

Part A answer is B 40% Part B answer is B 17.17 and i am not sure of part c

Step-by-step explanation:

I know these are right because my teacher gave me some of the answers

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Will you please help me

PtichkaEL [24]

Answer:

sure if im able, with what?

Step-by-step explanation:

4 0

3 years ago

Which of the following sets of inequalities

Ludmilka [50]

Inequalities help us to compare two unequal expressions. The correct options are 2 and 3.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The inequality for the red portion is,

slope, m = (-2/-4) = 1/2

y-intercept is 2.

y ≤ (1/2)x + 2

The inequality for the blue portion is,
slope, m = (5-0)/(3-0.5) = 2

y-intercept is -1.

y > 2x - 1

Hence, the correct options are 2 and 3.

Learn more about Inequality:

brainly.com/question/19491153

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7 0

2 years ago

The real number 7/12 belongs to which set of numbers

IRISSAK [1]

Rational numbers.
Please give brainliest and have a great day!

7 0

3 years ago

2(y-3)-y=-1 please help me with this one

emmasim [6.3K]

Y=<span>5 is your answer. Hope this helps :)</span>

5 0

3 years ago

Solve the following initial-value problem:<br><br> (ex+y)dx+(3+x+yey)dy=0, y(0)=1<br><br> 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

3 years ago