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horsena [70]
3 years ago
7

Part A- What is the discount rate at the store closing?

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0
1 question I believe it’s A. 2 question I believe it’s C. 3 question I believe it’s B. Hope this help❤️.
MatroZZZ [7]3 years ago
6 0

Answer:

Part A answer is B 40% Part B answer is B 17.17 and i am not sure of part c

Step-by-step explanation:

I know these are right because my teacher gave me some of the answers

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Solve for n<br><br> 5 5/6 +n = 10 1/12
Kobotan [32]

Answer:

Exact form:

N = 17/4

Decimal form:

N = 4.25

Mixed Number form:

N = 4 1/4

Step-by-step explanation:

Solve for N by simplifying both sides of the equation, then isolating the variable.

4 0
3 years ago
What is the answer for -1.2(-3.05)
gregori [183]
The answer is 3.66 (it’s a positive number because the two negatives cancel each other out)
5 0
3 years ago
-a^2b^2c^2(a+b-c) find the product
irakobra [83]

Answer:

-a^3b^2c^2-a^2b^3c^2+a^2b^2c^3

I hope it will be useful.

5 0
3 years ago
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
Tom has 28 milk chocolates and emily has 24 dark chocolates they have to divide these chocolates into small packets that each ha
nignag [31]

Answer: the maximum number of packets they can make i 4 packets to make the maximum number of packets, each packet should have 7 milk chocolates and 6 dark chocolates. If that does not work then there can be 2 packets with 14 milk chocolates and 12 dark chocolates.

Step-by-step explanation:

This is hurting my brain ngl

Hope this helps though ;)

4 0
3 years ago
Read 2 more answers
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