PLEASE HELP PLEASE HELP PLEASE

Draw a solid with the following front, side, and top views.

Lapatulllka [165]

It is a rectangular pyramid
should i explain?
fell free to tell me if it doesn't make sense :)

4 0

2 years ago

Select the correct answer.

jenyasd209 [6]

The expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)

A cubic equation in algebra is a one-variable equation of the form ax3+bx2+cx+d=0 where an is nonzero. The roots of the cubic function defined by the left side of this equation are the solutions to this equation.

Given expression 2x³-3x²-3x+2 whose one of factor is (x-2)

We have to find second factor of given equation

First we will be rational root theorem to given expression so will get following expression:

$\left(x+1\right)\frac{2x^3-3x^2-3x+2}{x+1}$

So one factor is (x-1) and now simplifying $\frac{2x^3-3x^2-3x+2}{x+1}$ we get 2x² - 5x +2 and the factor of 2x² - 5x +2 will be (2x-1)(x-2)

Hence the expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)

Learn more about Polynomial here:

brainly.com/question/4142886

#SPJ10

4 0

2 years ago

INSTRUCTIONS<br> Solve the division problems<br> Name

skad [1K]

Answer:

13

Step-by-step explanation:

Do the divison! :D It's hard to write out on here, but you can find a lot of other online resources on how to do it, I reccomend Khan Academy.

5 0

2 years ago

Please hepl with math

Ivenika [448]

Answer:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

Step-by-step explanation:

We are given the expression to be simplified:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}$

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

$a^{p+q} = a^p \times a^q$

Let us use it to solve the powers of 5 in the given expression.

$\therefore$ we can write:

$5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}$

$5^{n+1} = 5^n\times 5$

The given expression becomes:

$\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}$

Taking common $5^{n+1}$ from the numerator and

Taking common $5^{n}$ from the denominator

$\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}$

$\therefore$ The answer is:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

6 0

3 years ago

Three examples of front end estimation

BARSIC [14]

Answer: 20, 300, -50, 1,000, 80,000. Take the number 32; the choices to replace it with are 30 or 40 (they both have only one non-zero digit).

Step-by-step explanation: In front-end estimation, we replace the original number with a number that's close by but only has one non-zero digit.

5 0

2 years ago

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